Maximal regularity and applications to PDEs 273
endowed with the norm
kuk
E
T
= sup
0<t<T
ku(t)k
n
+ sup
0<t<T
√
tk∇u(t)k
n
.
We are looking for u ∈ E
T
solution of u = a + B(u, u) where B is defined by
B(u, v)(t) = −P
Z
t
0
e
(t−s)∆
³
1
2
∇·(u(s) ⊗v(s) +v(s) ⊗u(s))
´
ds, t ∈ [0, T ], (4.5)
and a(t) = e
t∆
u
0
, t ∈ [0, T ].
Theorem 4.8 (G. Furioli, P. G. Lemarié–Rieusset, E. Terraneo, 2000). Let u
1
, u
2
be
two integral solutions of (4.4) for the same initial value u
0
∈ L
n
(R
n
; R
n
) satisfying
div u
0
= 0. Then u
1
= u
2
on [0, T ].
Proof. This result was first proved by G. Furioli, P. G. Lemarié–Rieusset and E. Ter-
raneo in [18] (see also the very nice review on the subject by M. Cannone [11]). The
proof presented here is based on [33] and of the same spirit as the proof of Theo-
rem 4.3. The basic idea is to reformulate the problem of uniqueness as to show that
u = u
1
−u
2
is equal to zero on the interval [0, T ]. The function u satisfies the equation
u = B(u, u
1
+ u
2
) where B is defined by (4.5) above. As shown by F. Oru [35], the
bilinear operator
B : C ([0, T ]; L
n
(R
n
; R
n
)) ×C ([0, T ]; L
n
(R
n
; R
n
)) → C ([0, T ]; L
n
(R
n
; R
n
))
is not bounded. Had it been continuous, the proof of uniqueness of an integral solution
of the Navier–Stokes system would have been straightforward. The idea of [18], in
dimension n = 3, was then to lower the regularity of the space L
3
(R
3
; R
3
) and to
consider a Besov space E instead (or, as shown by Y. Meyer in [31], the weak L
3
space, namely L
3,∞
(R
3
; R
3
)) to obtain a bounded bilinear operator B in C ([0, T ]; E)×
C ([0, T ]; E).
The proof of [33] relies on a slightly different idea: instead of weaken the regularity
of the space in the x-variable, we consider a Lebesgue space L
p
in time instead of the
space of continuous functions in time. As in the proof of Theorem 4.3, we write
u = B(u, u
1
− u
0
) + B(u, u
2
− u
0
) + 2B(u, u
0
− u
0,ε
) + 2B(u, u
0,ε
),
where u
0,ε
is chosen in C
∞
c
(R
n
; R
n
) close to u
0
in the L
n
-norm. To be able to show
that u = 0 on a small interval [0, τ ] (τ > 0) with the same method as in the proof of
Theorem 4.3, we only need a result of the same kind as Lemma 4.4, see Lemma 4.9
below. At that point, the argument goes exactly as before.
Lemma 4.9. The bilinear operator
B : L
p
(0, T ; L
n
(R
n
; R
n
)) ×C ([0, T ]; L
n
(R
n
; R
n
)) → L
p
(0, T ; L
n
(R
n
; R
n
))
is bounded for all p ∈]1, ∞[. More precisely, for all p ∈]1, ∞[, there exists a constant
c
p
> 0 such that for all u ∈ L
p
(0, T ; L
n
(R
n
; R
n
)) and all v ∈ C ([0, T ]; L
n
(R
n
; R
n
)),
we have
kB(u, v)k
L
p
(0,T ;L
n
(R
n
;R
n
))
≤ c
p
kuk
L
p
(0,T ;L
n
(R
n
;R
n
))
kvk
C ([0,T ];L
n
(R
n
;R
n
))
.