46
Laplace and Saddle Point Method
00
C(cp)(A.)
- I
A.
-kcp(k)
(0)
(IAI
~
00, A E Sf:)
k=O
Interior Nondegenerate Maximum Point
Let now
Sand
cp
be smooth functions and the function S have a maximum
at an interior point
Xo
of
the interval
[a,
b], i.e. a <
Xo
<
b.
Then
S/(xo)
=
O.
Assume, for simplicity, that S"(x
o
) <
O.
Then
S"
(x
o
)
<
O.
In other words, in a neighborhood
of
Xo
the function S has the following Taylor
expansion
2
Sex)
=S(xo)+S"(xo)
(x-xo)
+O«x-xO)3).
2
Such a point is called nondegenerate critical point. Then, as
A.
~
00
the
main contribution to the integral comes from a small neighborhood
of
xO.
In this neighborhood the function
<p
is almost constant and can be replaced
by its value at
xO.
The terms
of
order (x - x
O
)3
can be neglected in the exponent
and the remaining integral can be extended to the whole real line. By using
the standard Gaussian integral
roo
ex
p
( -
~
y2
)dy
==
fl.,
(Re
(l
>
0),
one obtains finally the main term
of
the asymptotics
'I
A -112
~<p(x
)eA.S(x
o
)
F(II.)-
V~
0
One can prove the general theorem.
Theorem: Let M =
[a,
b]
and
cp,
S E
CO
(M), S has a maximum only at
one point x
o
' a
<
Xo
<
band
S"(x
o
)
*
O.
Then as
A.
~
00,
A E
SE
there is
asymptotic expansion
00
F
(A.)
-
eA.S(xo)
I
Ck
A
-1I2-k
.
k=O
The coefficients c
k
are expressed in terms
of
derivatives
of
<p
and S at
xO.
The theorem can be proved as follows. First, we change the integration variable
x =
Xo
+ A
-ll2y.
So, y is the scaled fluctuation from the maximum point
xO.
The interval
of
integration should be changed accordingly, so that the maximum point is
now
y
==
O.
Then, we expand both functions
Sand
<p
in
Taylor series at
Xo
getting