4.1 The matrix operator method 91
Here B
g
and A
g
are the thermal emission of the ground and the albedo of the
isotropically reflecting ground, respectively. The assumption of isotropic ground
reflection leads to the following form of the (s × s) reflection matrix r
m
g
r
m
g
= 2 A
g
µ
1
w
1
... µ
s
w
s
.
.
.
.
.
.
.
.
.
µ
1
w
1
... µ
s
w
s
δ
0m
(4.18)
Note that for isotropy the reflection matrix r
m
g
is independent of the azimuthal
expansion index m. The derivation of this particular form for r
m
g
will be given in
the Appendix to this chapter.
In addition to the reflection at the ground we need to specify the boundary
conditions for the diffuse radiation at the top of the atmosphere and at the ground.
Usually, external diffuse illumination will be ignored, that is
I
m
−
(τ = 0) = 0, I
m
+
(τ
N +1
) = 0, I
m
−
(τ
N +1
) = 0 (4.19)
In the following we will summarize the main steps of the MOM. The algorithm
proceeds in the following way.
(1) Calculation of the optical properties.
(i) First calculate the optical properties of the elementary layers by means of (4.13).
(ii) Utilizing the adding and doubling formulas (4.15) and (4.16), the optical properties
of all homogeneous sublayers (i, i + 1), i = 0,...,N are calculated.
(iii) The optical properties of the combined layer (0, 2) are calculated by means of (4.7)
and (4.8).
(iv) The combined layer (0, 3) is obtained by again applying the addition theorems
(4.7) and (4.8) to the sublayers (0, 2) and (2, 3).
(v) This procedure is continued until the optical properties of all required combinations
of sublayers (i, j), i = 0,...,N , j = 0,...,N are determined.
(vi) Utilizing the special properties of the fictitious layer (N, N + 1) as listed in (4.17),
the optical properties of the total layer (0, N + 1) are obtained by replacing in (4.7)
and (4.8) 1 → N and 2 → N + 1. This yields
t
m
(N + 1, 0) =0, t
m
(0, N + 1) = 0
r
m
(0, N + 1) =r
m
(0, N ) + t
m
(N , 0)
E − r
m
g
r
m
(N , 0)
−1
r
m
g
t
m
(0, N )
r
m
(N + 1, 0) =0
J
m
−,1
(0, N + 1) =0, J
m
−,2
(0, N + 1) = 0
J
m
+,1
(N + 1, 0) =J
m
+,1
(N , 0) + t
m
(N , 0)
E − r
m
g
r
m
(N , 0)
−1
×
J
m
+,1
(N + 1, N ) + r
m
g
J
m
−,1
(0, N )
J
m
+,2
(N + 1, 0) =J
m
+,2
(N , 0) + t
m
(N , 0)
E − r
m
g
r
m
(N , 0)
−1
×
J
m
+,2
(N + 1, N ) + r
m
g
J
m
−,2
(0, N )
(4.20)