5. A nonlinear Trotter product formula 359
These conditions are also enough to yield the boundedness of the maps X W V !
V and Y W V V ! L.W /,in(5.31), but in order to have boundedness of
Y W V V ! L.V /, we need C
1
-bounds on Y.f;g/, hence C
1
-bounds on DX .
In other words, we need X 2 BC
2
.R
`
/. We have the following result.
Proposition 5.2. Let u 2 C
Œ0; T ; BC
1
.R
n
/
solve (5.1), and let v.t/ be defined
by (5.4)–(5.5). Assume that L is a constant-coefficient,second-order, elliptic oper-
ator, generating a contraction semigroup on BC
0
.R
n
/ and that X is a vector field
on R
`
with coefficients in BC
2
.R
`
/. Then, for any bounded interval t 2 Œ0; T ,
(5.42) ku.t/ v.t/k
BC
1
C
kf k
BC
1
n
1=2
:
As another example of Banach spaces to which Proposition 5.1 applies,
consider
(5.43) V D H
k
.R
n
/; W D H
k2
.R
n
/; k >
n
2
;0<<1:
Assume k 2 Z
C
.Then(5.28) holds, with ı D . We have the Moser estimate
(5.44) kX.f /k
H
k
C
k
kf k
L
1
1 Ckf k
H
k
;
where
(5.45) C
k
./ D C
0
k
sup
˚
X
./
.f / Wjf j; jjk
:
Thus (5.31) is seen to hold as long as X 2 BC
k
.R
`
/. To see whether (5.30) holds,
we estimate .d=dt/kF
t
f k
2
H
k
, exploiting (5.44) to obtain
(5.46)
d
dt
kF
t
f k
2
H
k
D 2
X.F
t
f/;F
t
f
H
k
C
k
kF
t
f k
L
1
kF
t
f k
H
k
CkF
t
f k
2
H
k
:
Now for kF
t
f k
H
k
1, the right side is 2C
k
kF
t
f k
L
1
kF
t
k
2
H
k
.IfX 2
BC
k
.R
`
/, there is a bound on 2C
k
kF
t
f k
L
1
strong enough to yield (5.30).
We have the following result:
Proposition 5.3. Assume k>n=2is an integer. Let u 2 C
Œ0; T ; H
k
.R
n
/
solve (5.1), and let v.t/ be defined by (5.4)–(5.5). Assume that L is a constant-
coefficient, second-order, elliptic operator, generating a contraction semigroup on
L
2
.R
n
/, and that X is a vector field on R
`
with coefficients in BC
k
.R
`
/. Then,
for any bounded interval t 2 Œ0; T ,
(5.47) ku.t/ v.t/k
H
k
C
kf k
H
k
n
;