First let us take the case where . Applying the Mean Value Theorem to on the
interval , we get a number , with , such that
Since on , we know from the Increasing/Decreasing Test that is increasing
on . Thus, since , we have
and so, multiplying this inequality by the positive number , we get
Now we add to both sides of this inequality:
But from Equation 1 we have . So this inequality becomes
which is what we wanted to prove.
For the case where we have , but multiplication by the negative
number reverses the inequality, so we get (2) and (3) as before.
M
SECTION 7.1 THEOREM If is a one-to-one continuous function defined on an interval
, then its inverse function is also continuous.
PROOF First we show that if is both one-to-one and continuous on , then it must
be either increasing or decreasing on . If it were neither increasing nor decreasing,
then there would exist numbers , , and in with such that
does not lie between and . There are two possibilities: either (1) lies
between and or (2) lies between and . (Draw a picture.) In
case (1) we apply the Intermediate Value Theorem to the continuous function to get a
number between and such that . In case (2) the Intermediate Value
Theorem gives a number between and such that . In either case we
have contradicted the fact that is one-to-one.
Let us assume, for the sake of definiteness, that is increasing on . We take any
number in the domain of and we let ; that is, is the number in
such that . To show that is continuous at we take any such
that the interval is contained in the interval . Since is increasing,
it maps the numbers in the interval onto the numbers in the interval
and reverses the correspondence. If we let denote the
smaller of the numbers and , then the interval
is contained in the interval and so is mapped
into the interval by . (See the arrow diagram in Figure 3.) We have
therefore found a number such that
ⱍ
f
⫺1
共y兲 ⫺ f
⫺1
共y
0
兲
ⱍ
⬍
then
ⱍ
y ⫺ y
0
ⱍ
⬍
␦
if
␦
⬎ 0
f
⫺1
共x
0
⫺, x
0
⫹兲
共 f 共x
0
⫺兲, f 共x
0
⫹兲兲共y
0
⫺
␦
, y
0
⫹
␦
兲
␦
2
苷 f 共x
0
⫹兲 ⫺ y
0
␦
1
苷 y
0
⫺ f 共x
0
⫺兲
␦
f
⫺1
共 f 共x
0
⫺兲, f 共x
0
⫹兲兲
共x
0
⫺, x
0
⫹兲
f共a, b兲共x
0
⫺, x
0
⫹兲
⬎0y
0
f
⫺1
f 共x
0
兲 苷 y
0
共a, b兲
x
0
f
⫺1
共y
0
兲 苷 x
0
f
⫺1
y
0
共a, b兲f
f
f 共c兲 苷 f 共x
1
兲x
3
x
2
c
f 共c兲 苷 f 共x
3
兲x
2
x
1
c
f
f 共x
3
兲f 共x
2
兲f 共x
1
兲f 共x
2
兲f 共x
1
兲
f 共x
3
兲f 共x
3
兲f 共x
1
兲
f 共x
2
兲x
1
⬍
x
2
⬍
x
3
共a, b兲x
3
x
2
x
1
共a, b兲
共a, b兲f
f
⫺1
共a, b兲
f
6
x ⫺ a
f ⬘共c兲
⬍
f ⬘共a兲x
⬍
a
f 共x兲 ⬎ f 共a兲 ⫹ f ⬘共a兲共x ⫺ a兲
3
f 共x兲 苷 f 共a兲 ⫹ f ⬘共c兲共x ⫺ a兲
f 共a兲 ⫹ f ⬘共a兲共x ⫺ a兲
⬍
f 共a兲 ⫹ f ⬘共c兲共x ⫺ a兲
f 共a兲
f ⬘共a兲共x ⫺ a兲
⬍
f ⬘共c兲共x ⫺ a兲
2
x ⫺ a
f ⬘共a兲
⬍
f ⬘共c兲
a
⬍
cI
f ⬘If ⬙⬎0
f 共x兲 ⫺ f 共a兲 苷 f ⬘共c兲共x ⫺ a兲
1
a
⬍
c
⬍
xc关a, x兴
fx ⬎ a
A44
||||
APPENDIX F PROOFS OF THEOREMS