EFFECTIVELY EARTHED SYSTEMS
Earth Fault Protection
for worldwide cooperation
205
BA THS / BU Transmission Systems and Substations
LEC Support Programme
The fault resistance “R
f
”, consists of the arc resistance and the
tower foot resistance. The arc resistance is calculated by the for-
mula:
R
arc
= 28700a / I
f
1.4
(according to Warrington)
where “a”, is the arc length in meter, normally the insulator length,
and “I
f
” is the fault current in “A”.
A calculation will show that values will differs from below 1 Ω for
heavy faults, up to 50-400 Ω for high resistive earth faults.
The tower foot resistance depends on the earthing effectiveness
of the towers, whether top lines are used etc. For the tower foot
resistance values from below 10 Ω up to 50 Ω have been docu-
mented.
2.2 NEUTRAL POINT VOLTAGES
The occurring neutral point voltage, at different locations, can be
seen in figure 2. The designate “U
0
”, represents the neutral point
voltage (3U
0
= U
N
). It’s to be noted that “U
0
” is generated by the
earth fault current “I
0
” through the zero sequence source. This im-
plies that the angle between “U
0
” and “I
0
” is always equal to the
zero sequence source angle, independent of the fault resistance
and the angle between the faulty phase voltage and the line cur-
rent in the faulty phase.
It must also be noted that “U
N
” will be very low when sensitive
earth fault relays are used in a strong network with low zero se-
quence source impedances.
As an example we can use the 132kV network according to figure
1 and 2. With an “I
N
” setting of 120A, the “I
0
” is 40A and with a
zero sequence source impedance of say 20 Ω, the zero se-
quence voltage component “U
0
” will be 40x10 = 400V and “3U
0
”
will then be 1200V. This will, with an open delta winding with 110V