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6.3 Cox-Ingersoll-Ross Processes 357
6.3.1 CIR Processes and BESQ
From Theorem 1.5.5.1 on the solutions to SDE, the equation
dr
t
= k(θ − r
t
) dt + σ
|r
t
|dW
t
,r
0
= x (6.3.1)
admits a unique solution which is strong. For θ =0andx = 0, the solution
is r
t
= 0, and from the comparison Theorem 1.5.5.9, we deduce that, in the
case kθ > 0, r
t
≥ 0forx ≥ 0. In that case, we omit the absolute value and
consider the positive solution of
dr
t
= k(θ − r
t
) dt + σ
√
r
t
dW
t
,r
0
= x. (6.3.2)
This solution is called a Cox-Ingersoll-Ross (CIR) process or a square-root
process (See Feller [342]). For σ = 2, this process is the square of the norm
of a δ-dimensional OU process, with dimension δ = kθ (see Subsection 2.6.5
and the previous Subsection 6.2.6), but this equation also makes sense even
if δ is not an integer.
We shall denote by
k
Q
kθ,σ
the law of the CIR process solution of the
equation (6.3.1). In the case σ =2,wesimplywrite
k
Q
kθ,2
=
k
Q
kθ
.Now,
the elementary change of time A(t)=4t/σ
2
reduces the study of the solution
of (6.3.2)tothecaseσ = 2: indeed, if Z
t
= r(4t/σ
2
), then
dZ
t
= k
(θ − Z
t
) dt +2
Z
t
dB
t
with k
=4k/σ
2
and B a Brownian motion.
Proposition 6.3.1.1 The CIR process (6.3.2)isaBESQprocesstrans-
formed by the following space-time changes:
r
t
= e
−kt
ρ
σ
2
4k
(e
kt
− 1)
where (ρ(s),s≥ 0) is a BESQ
δ
process, with dimension δ =
4kθ
σ
2
.
Proof: The proof is left as an exercise for the reader. A more general case
will be presented in the following Theorem 6.3.5.1.
It follows that for 2kθ ≥ σ
2
, a CIR process starting from a positive initial
point stays strictly positive. For 0 ≤ 2kθ < σ
2
, a CIR process starting from
a positive initial point hits 0 with probability p ∈]0, 1[ in the case k<0
(P(T
x
0
< ∞)=p) and almost surely if k ≥ 0(P(T
x
0
< ∞)=1).Inthecase
0 < 2kθ, the boundary 0 is instantaneously reflecting, whereas in the case
2kθ < 0, the process r starting from a positive initial point reaches 0 almost
surely. Let T
0
=inf{t : r
t
=0} and set Z
t
= −r
T
0
+t
. Then,
dZ
t
=(−δ + λZ
t
)dt + σ
|Z
t
|dB
t
where B is a BM. We know that Z
t
≥ 0, thus r
T
0
+t
takes values in R
−
.