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342 6 A Special Family of Diffusions: Bessel Processes
Exercise 6.1.5.7 Let R and R be two independent BES
3
processes. Prove
that the filtration generated by the process Y
t
= R
−1
t
−
R
−1
t
is the filtration
generated by the processes R and
R.
Hint: Indeed, the bracket of Y , i.e.,
t
0
(
1
R
4
s
+
1
e
R
4
s
)ds is adapted w.r.t. the
filtration (Y
t
,t≥ 0) generated by Y . Hence the process (
1
R
4
t
+
1
e
R
4
t
)isY-adapted.
Now, if a and b are given, there exists a unique pair (x, y) of positive numbers
such that x − y = a, x
4
+ y
4
= b (this pair can even be given explicitly,
noting that x
4
+ y
4
− (x − y)
4
=2xy(xy − 2(x − y)
2
)). This completes the
proof.
6.2 Properties
6.2.1 Additivity of BESQ’s
An important property, due to Shiga and Watanabe [788], is the additivity
of the BESQ family. Let us denote by P ∗ Q the convolution of P and Q,two
probabilities on C(R
+
, R
+
).
Proposition 6.2.1.1 The sum of two independent squared Bessel processes
with respective dimension δ and δ
, starting respectively from x and x
is a
squared Bessel process with dimension δ + δ
, starting from x + x
:
Q
δ
x
∗ Q
δ
y
= Q
δ+δ
x+y
.
Proof: Let X and Y be two independent BESQ processes starting at x
(resp. at y) and with dimension δ (resp. δ
)andZ = X + Y .Wewantto
show that Z is distributed as Q
δ+δ
x+y
. Note that the result is obvious from the
definition when the dimensions are integers (this is what D. Williams calls the
“Pythagoras” property). In the general case
Z
t
= x + y +(δ + δ
)t +2
t
0
X
s
dB
s
+
Y
s
dB
s
,
where (B,B
) is a two-dimensional Brownian motion. This process satisfies
t
0
1
{Z
s
=0}
ds =0.Let
B be a third Brownian motion independent of (B,B
).
The process W defined as
W
t
=
t
0
1
{Z
s
>0}
√
X
s
dB
s
+
√
Y
s
dB
s
√
Z
s
is a Brownian motion (it is a martingale with increasing process equal to t).
The process Z satisfies
Z
t
= x + y +(δ + δ
)t +2
t
0
Z
s
dW
s
,
and this equation admits a unique solution in law.