
IV.6 Existence, Uniqueness, and L
q
-Estimates in a Bounded Domain 285
Exercise IV.6.3 Show that the first [respectively, second] part of Theorem IV.6.1
continues to hold if ∇ · v = g 6≡ 0, with g ∈ W
m+1,q
(Ω) [respectively, g ∈ L
q
(Ω)]
and
Z
Ω
g =
Z
∂Ω
v
∗
· n.
Inequality (IV.6.10) [respectively, (IV.6.11)] is t hen accordingly modified by adding
to its right-hand side the term
kgk
m+1,q
, [respectively, kgk
q
].
Hint: Use Exercise IV.4.2, Exercise IV.5.2, Exercise IV.4.3, and Exercise IV .5.4,
together with the reasonings employed to arrive at Theorem IV.6.1.
We end this section by proving a further useful estimate satisfied by
the pressure field p, in addition to those already provided by (IV.6.1 0) and
(IV.6.11). Specifically, we have
Theorem IV.6.2 Let Ω be a bounded domain of R
n
, n ≥ 2, of class C
2
,
and let (v, p) ∈ W
2,q
(Ω) × W
1,q
(Ω) be a solution to (IV.0.1), corresponding
to f ∈ H
q
(Ω), fo r some q ∈ (1, ∞).
3
Furthermore, we norm alize p by the
condition p
Ω
= 0. Then, given ε > 0, there exists c = c(Ω, n, q, r, ε) such that
kpk
q
≤ c |v|
1,q
+ ε kvk
2,r
,
for any r ∈ [ q(n−1)/n, q], if q > n/(n−1), and any r ∈ (1, q], if q ≤ n/(n−1).
Proof. We dot-multiply both sides of (IV.0.1) by ∇ϕ, ϕ ∈ W
1,q
0
(Ω), to obtain
Z
Ω
∆v · ∇ϕ =
Z
Ω
∇p · ∇ϕ , for all ϕ ∈ W
1,q
0
(Ω) . (IV.6.13)
We then choose ϕ as the solution to the following Neumann problem
∆ϕ = g −g
Ω
in Ω ,
∂ϕ
∂n
∂Ω
= 0 ,
Z
Ω
ϕ = 0 , (IV.6.14 )
where g ∈ L
q
0
(Ω). From a classical result of Agmon, Douglis & Nirenberg
(1959, §15), it follows that this problem has one and only one sol ution ϕ ∈
W
2,q
0
(Ω), which, in addi tion, satisfies the estimate
kϕk
2,q
0
≤ c kgk
q
0
, (IV.6.15)
for some c = c(Ω, q, n). Thus, integrating by parts on the right-hand side of
(IV.6.13), using (IV. 6.14), and the condition p
Ω
= 0, we obtain
Z
Ω
∆v · ∇ϕ = −
Z
Ω
p g . (IV.6.16)
3
In view of the Helmholtz–Weyl decomposition Theorem III.1.2, we may assume,
without loss, f ∈ H
q
(Ω), instead of f ∈ L
q
(Ω).