
7 Partially Invariant Subspaces and GSV 343
and a DS for the remaining two coefficients C
1,2
is obtained,
C
1
= P(0, 0)C
2
1
+
2P(1, −1)A
3
+ 2P(
1
3
, −
1
3
)A
4
A
5
C
1+ρ
3
2
,
C
2
= 2P(0, 1)C
1
C
2
.
This can be integrated in quadratures and possesses blow-up solutions. For the thin
film operator (7.23), we obtain six extra conditions that imply existence of a four-
parameter family of TFEs possessing such exact solutions.
For the second-order PDE (7.11), the DS (7.27) with C
k
= ... admit, in general,
either exponential particular solutions C
k
(t) = A
k
e
ρ
k
t
with ρ
1
= 0, or the algebraic
ones (7.22), where ρ
1
=−2. If P(0, 1) = P(0, −1) = P(0,
1
3
) = P(0, −
1
3
),there
exist solutions C
k
(t) = A
k
C
2
(t) for k = 3, 4, 5, where C
1
(t) and C
2
(t) solve a DS,
and (7.26) give two extra conditions on {A
k
}.
7.1.2 On further extensions
1.
∂
∂t
-dependent operators. We considered such operators in Sections 1.5.2 (see
tially invariant modules), a similar computationalanalysis can be performed, though
the overdeterminedDSs becomemore cumbersome and difficult. We must admit that
there is a higher probability to obtain purely, in both x and t variables, exponential
solutions that sometimes can be more efficiently manipulated by using Baker–Hirota
derivatives and bilinear operators, or by other methods from theory of integrable
PDEs.
Example 7.8 (PDE with nonstationary part from the KdV equation) Let us be-
gin with the following rather artificial PDE:
u
x
u
t
− uu
xt
= F[u], (7.28)
where the quadratic left-hand side has been borrowed from the bilinear form of the
KdV equation (0.31) in the Introduction. Here F[u] is the general operator (7.1).
First, consider the expansion (7.4) with the same assumptions on the exponents.Not
specifying the DS, we claim that the only possible solutions are exponential ones,
C
k
(t) = A
k
e
ρ
k
t
for all k = 1, 2, 3, 4, (7.29)
where {ρ
k
} satisfies a number of conditions associated with the values of the poly-
nomial P at p
k
. One can think this rigid exponential solution structure as being as-
sociated with the specific form of the left-hand side of (7.28), which is a full Baker–
Hirota derivative −2Du · u
t
,defined as, [22, 284]:
Dv · w =
d
dz
v(x +z)w(x − z)
z=0
= v
x
w − vw
x
. (7.30)
Therefore,the Baker–Hirota method applies ensuring that the right solutions are sup-
posed to be of exponential soliton-type only.
Furthermore, for the PDE with the first term only on the left-hand side
u
x
u
t
= F[u], (7.31)
© 2007 by Taylor & Francis Group, LLC
(1.135)) and 2.7, where invariant modules were dealt with. For invariant sets (par-