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Dissipative Operators and Applications
D(A) provided by Lemma 3.6.5 is far from explicit, since it presupposes the
identification of the subspace K or, equivalently, of the nullspace of the operator
I - A A. Because of this, the usefulness of Lemma 3.6.5 is rather limited in this
context.
3.6.4
Remark. The argument in Theorem 3.6.2 proving that a m-dissipative
operator must be maximal dissipative extends without changes to the Banach space
case. This is not the case with the converse, as the following counterexample shows.
3.6.5 Example (Lumer-Phillips [1961: 1]). Let E = Co.1 [0,11R and Au = u', where
D(A) is the set of all u E E such that Au' G E. Then (a) A is maximal dissipative,
and (b) (I-A)D(A)*E.
We note also that Lemma 3.6.3 fails in the Banach space case, since an
operator as the one in Example 3.6.5 is not m-dissipative and, being maximal
dissipative, does not admit dissipative extensions at all. We note in passing that
every dissipative operator (not necessarily closed or densely defined) in an arbitrary
Banach space E can be extended to a maximal dissipative operator by a standard
application of Zorn's lemma. This is slightly more general than Lemma 3.6.3 even in
the Hilbert space case, although the extension is even more esoteric.
Theorems 3.6.1 and 3.1.9 have interesting interpretations in Hilbert
spaces. Observe that both relations (3.6.3) and (3.6.4) coalesce into
Re(Au, u) = 0
(u E D(A)).
(3.6.13)
It follows that the operator A is conservative if and only if B = - iA is
symmetric. In fact, assume B is symmetric. Then (iBu, u) = - i(Bu, u),
where (Bu, u) is real, thus iB is conservative. On the other hand, let A be
conservative. Taking real parts in the identity (A(u + v), u + v) = (Au, u)+
(Au, v)+(Av, u)+(Av, v), we obtain
Re(Au,v)+Re(u,Av)=0 (u,veD(A)). (3.6.14)
Applying (3.6.14) to iu, v and adding the two equalities, we obtain (Au, v)+
(v, Au)=0 or
(iAu, v) = (u, iAv), (3.6.15)
which shows that B = - iA is symmetric (of course, so is iA).
Condition (3.6.5) (say, for X = 1) can be written in terms of B as
follows:
(B+iI)D(B)=H,
while the same condition for - A is
(B-iI)D(B)=H.
(3.6.16)
(3.6.17)
Clearly (3.6.17) is equivalent to the vanishing of the negative deficiency
index d_ of B; likewise, (3.6.16) holds if and only if d+ = 0 and any of the
two conditions is equivalent to B being maximal symmetric (see Section 6).
We obtain in this way the following result.