restriction of F on this subset. This restriction is a continuous function on X
1
and
hence is 0 since X
1
is connected. Starting from every point of this subset, let now
x
2
run through X
2
to obtain again F 0 for the restriction of F. After n steps, F 0
on X in contradiction to the assumption that F is surjective. h
A concept seemingly related to connectedness but in fact independent is local
connectedness. A topological space is called locally connected, if every point has
a neighborhood base of connected neighborhoods. (Not just one neighborhood, all
neighborhoods of the base must be connected.)
A connected space need not be locally connected. For instance, consider the
subspace of R
2
consisting of a horizontal axis and vertical lines through all rational
points on the horizontal axis, in the relative topology deduced from the usual
topology of the R
2
: It is connected, but no point off the horizontal axis has a
neighborhood base of only connected sets. (Compare the above statement on Q:)On
the other hand, every discrete space with more than one point, although it is totally
disconnected, is locally connected! Indeed, since every one point set is open and
connected in this case, it forms a connected neighborhood base of the point. (Check
it.) This seems all odd, nevertheless local connectedness is an important concept.
A topological space is locally connected, iff every connected component of an
open set is an open set. This is not the case in the above example with the vertical
lines through rational points of a horizontal axis, since the connected components
of open sets off the horizontal axis are not open.
Proof of the statement Pick any point x and any neighborhood of it and consider
the connected component of x in it. Since it is open, it is a neighborhood of x.
Hence, x has a neighborhood base of connected sets, and the condition of the
theorem is sufficient. Reversely, let A be an open set in a locally connected space,
A
0
one of its connected components and x any point of A
0
. Let U be a neighborhood
of x in A. It contains a connected neighborhood of x which thus is in A
0
. Hence, x is
an inner point of A
0
and, since x was chosen arbitrarily, A
0
is open. h
As a consequence, a locally connected space is a collection of its connected
components which are all open-closed.
A topological quotient space of a locally connected space is locally connected.
Proof Let X be locally connected and let p : X ! X=R be the canonical projec-
tion. Let U X=R be an open set and U
0
one of its connected components. Let
x 2 p
1
ðU
0
Þ, and let A be the connected component of x in p
1
ðUÞ. Then, pðAÞ is
connected (since p is continuous) and contains pðxÞ. Hence, pðAÞU
0
and A
p
1
ðU
0
Þ: Since X is locally connected and p
1
ðUÞ is open (again because p is
continuous), p
1
ðU
0
Þ is also open due to the previous theorem. Now, by the
definition of the quotient topology, U
0
is also open, and the previous theorem in the
opposite direction says that X=R is locally connected. h
The subsequently discussed further concepts of connectedness are based on
homotopy. Let I ¼½0; 1 be the closed real unit interval. Two continuous functions
40 2 Topology