In a sense inverse to the above is the following theorem:
Each connected Lie group G has a simply connected covering space
G which is
again a Lie group and the covering p :
G ! G is a Lie group homomorphism the
kernel of which is a discrete subgroup of
G:
Proof It was already seen that G has a simply connected covering space
G:
Choose an arbitrary element of p
1
ðeÞ (where e is the unit of G) to be the unit
e of
G: Let
F
g
and
F
h
be two paths in
G from
e to arbitrarily chosen points
g and
h;
respectively. Let F
g
¼ pð
F
g
Þ; F
h
¼ pð
F
h
Þ; g ¼ pð
gÞ and h ¼ pð
hÞ: Let F
0
¼
gF
h
F
g
be the path in G obtained by concatenation of F
g
and the g-translated image
of F
h
and let
F
0
be a path in
G starting at
e and being projected by p onto F
0
: Its
end point
k depends only on
g and
h and not on the particular paths chosen. Indeed,
let
F
0
g
and
F
0
h
alternatively chosen paths, let F
0
g
and F
0
h
be their projections, and
let
F
00
be a path starting at
e and being projected onto F
00
¼ gF
0
h
F
0
g
: Since
½F
0
g
F
g
; ½F
0
h
F
h
2qðp;
eÞ and ðFF
0
Þ
¼ F
0
F
; it follows that F
00
F
0
¼ðgF
0
h
F
0
g
Þ
ðgF
h
F
g
Þ¼F
0
g
gF
0
h
gF
h
F
g
ffiðF
0
g
F
g
ÞðF
0
h
F
h
Þ; and hence ½F
00
F
0
2qðp;
eÞ with
the consequence that F
0
and F
00
; both starting at
e; have the same end point
k: On
this basis, the product
g
h ¼
k in
G is correctly defined, and by considering cor-
responding paths associativity of this product, unit property of
e and the existence
of
g
1
is demonstrated. Furthermore, pð
g
hÞ¼pð
gÞpð
hÞ was underlying the con-
struction of the product. Hence,
g is a group and the covering p is a group
homomorphism.
It remains to show that the product
g
h
1
is smooth in
G: This is straightfor-
wardly demonstrated with the help of paths F
s
ðtÞ¼FðstÞ smoothly depending on s
in G and using the fact that p is a local diffeomorphism.
Finally, since p is a covering, there is a neighborhood U of e in G the preimage
of which consists of disjoint open sets of
G homeomorphic with U: In particular,
the preimage of e which is the kernel of the homomorphism p is discrete. h
Hence, for every connected Lie group G there exists a simply connected Lie
group
G which is a covering of G: The natural question arises, whether and in
which sense
G is unambiguously determined. It was already demonstrated that
simply connected coverings of G are diffeomorphic as manifolds. That they are
also isomorphic as groups follows from the connection between the Lie groups and
their Lie algebras.
Let G and H be connected Lie groups, and let F : G ! H be a Lie group
homomorphism. Then F is a covering, iff F
: g ! h is a Lie algebra isomorphism.
Proof Suppose that F is a covering. Then F
must be injective. Otherwise F
:
T
g
ðGÞ!T
FðgÞ
ðHÞ would have a non-trivial kernel at every point g: These kernels
form an involutive distribution having an integral manifold (Frobenius theorem)
which is mapped into a point of H by F; and F could not be a local homeomor-
phism. F
must also be surjective, since otherwise F would define a proper
6.4 Simply Connected Covering Group 187