
9.1 Measurements in Schwarzschild space-time 191
At r =3M we have ζ
K
=
˜
ζ; hence S(U)
ˆ
φ
ˆ
φ
|
3M
= ζ
2
K
|
3M
, independent of ζ.
Since the Fermi rotation of the frame is zero at r =3M, the azimuthal strain
only needs to balance a tidal compression; hence the
ˆ
φ-component of the tidal
curvature tensor is itself independent of ζ. The above result is consistent with the
independence of the thrust from ζ, as first noticed by Abramowicz and Lasota
(1974). If the observer is at rest with respect to infinity, i.e. if ζ = 0, then
S(U)
ˆ
φ
ˆ
φ
= ζ
2
K
> 0, meaning a stretch, so the measurement of this strain would
not help us understand whether the observer is at rest or not.
The relative strain in the latitudinal direction is, from (9.12), given by
S(U)
ˆ
θ
ˆ
θ
=
ζ
2
K
−
2M
r
(ζ
2
K
− ζ
2
)
r
2
(ζ
2
c
− ζ
2
)
. (9.19)
As can be seen from Fig. 9.1, S(U)
ˆ
θ
ˆ
θ
is always positive, meaning that in the
θ direction a stretch is needed to ensure rigidity. If the observer is at rest,
then from (9.12) we would have S(U)
ˆ
θ
ˆ
θ
= ζ
2
K
= S(U)
ˆ
φ
ˆ
φ
> 0. In this case,
if one knows the local radial direction, the measurement of the strains in any
two directions orthogonal to each other and to the radial one would unambigu-
ously indicate that the observer is at rest, if these two strains are positive and
equal to each other, independent of rotation in the plane orthogonal to the radial
direction.
From the above analysis it follows that a direct measurement of the radial
S(U)
ˆrˆr
, latitudinal S(U)
ˆ
θ
ˆ
θ
, and azimuthal S(U)
ˆ
φ
ˆ
φ
strains allows one to deduce
in general that the observer is orbiting around a gravitational source (a black
hole, say), but they are not sufficient to let the observer recognize where in the
(ζ
2
,r)-plane of Fig. 9.2 he is actually orbiting. In fact, a measurement of the
azimuthal strain S(U)
ˆ
φ
ˆ
φ
would not allow the observer to distinguish between
orbiting with ζ in the range ζ
2
c
>ζ
2
>ζ
2
K
and in the range ζ
2
c
>ζ
2
>
˜
ζ
2
.In
both cases, in fact, S(U )
ˆ
φ
ˆ
φ
is negative (meaning a compression). Clearly, if he
can vary ζ and r then he would recognize that he was crossing the line ζ
2
=
˜
ζ
2
in the (ζ
2
,r)-plane if S(U)
ˆ
φ
ˆ
φ
vanishes but not the thrust, implying that the
corresponding circular orbit is not a geodesic.
Partially constrained circular motion
Let us now relax the rigidity condition imposed on the collection of particles and
allow free motion in the
ˆ
θ direction only. This condition is ensured by requiring
that a(U )
ˆ
θ
=0and∂
ˆ
θ
a(U)
ˆ
θ
=0foranyθ. This particular state of motion is
operationally set up by forcing the monitored particle to move inside a frictionless
narrowpipefixedintheθ direction. Calculating the above constraints from (8.28)
and imposing the resulting condition in (9.17)
2
, the relative acceleration in the
ˆ
θ direction becomes (de Felice and Usseglio-Tomasset, 1992)