9.4 Lyapunov’s theorem 201
parameter ρ, such that ρ =0corresponds to the equilibrium solution and that the
period T (ρ) is analytic in ρ with T (0) =
2π
|λ
1
|
.
Proof. We look for a solution w
= w(ξ, η)asapowerseriesofsomeunknown
functions ξ = ξ(t), η = η(t). Then, Hamilton’s equations ˙w
= JH
w
(w) become
w
ξ
˙
ξ + w
η
˙η = JH
w
(w) . (9.28)
We assume that ξ, η satisfy the relations
˙
ξ = αξ , ˙η = βη (9.29)
with α, β being suitable power series in ξ, η. We next perform a linear canonical
transformation, say w
= Cz, for some constant matrix C, such that the linearized
matrix is transformed into C
T
JLC = Λ,whereΛ is the diagonal matrix with
non–zero elements λ
1
, ..., λ
n
, −λ
1
, ..., −λ
n
. Moreover, the matrix C is chosen
to be symplectic and such that its components are suitably normalized according
to [162]. With this transformation, equation (9.28) takes the form
z
ξ
ξα + z
η
ηβ − Λz = g(z) , (9.30)
where
g
(z) ≡ C
−1
J(C
−1
)
T
H
z
(Cz) − Λz .
In order to determine uniquely the power series z
k
(ξ,η)(k =1,...,2n), α(ξ, η),
β(ξ, η), by comparison of the coefficients in (9.30), one needs to impose the following
compatibility conditions:
(C1) z
1
− ξ, z
2
− η, z
3
, ..., z
2n
start with quadratic terms;
(C2) there are no terms of the form ξ(ξη)
in z
1
−ξ and no terms of the form η(ξη)
in z
2
− η;
(C3) the series for α and β depend only on the quantity ω ≡ ξη.
By induction, one easily proves that equation (9.29) can be effectively solved
and that the coefficients are uniquely determined. The constant terms of α and β
are, respectively, λ
1
and −λ
1
. Moreover, it can be shown (see [162]) that α and β
satisfy the relation
α + β = 0 (9.31)
and that the Hamiltonian H becomes a series of ω = ξη. Referring to [162] for the
proof of the convergence of the series z
k
(ξ,η)(k =1,...,2n), α, β for sufficiently
small values of |ξ|, |η|, by (9.31) one finds that
dω
dt
=
˙
ξη + ξ ˙η =(α + β)ξη =(α + β)ω =0;
therefore ω, α, β do not depend on the time and consequently from (9.29) one
obtains
ξ = ξ
0
e
αt
,η= η
0
e
βt
, (9.32)