184 14. Nonlinear Elliptic Equations
then, as in formula (1.30), we see that the Gauss curvature k of M in the new
metric is
(7.46) k D .v C K/e
2v
D 0I
in other words, the metric g
0
D .1 C ˆ/
2
g is flat! Using this observation, we can
establish the following remarkable theorem of S. Bernstein:
Theorem 7.8. If u W R
2
! R is an everywhere-defined C
2
-solution to the mini-
mal surface equation, then u is a linear function.
Proof. Consider the minimal surface M given by z D u.x/; x 2 R
2
,inthe
metric g
0
D .1 C ˆ/
2
g, which, as we have seen, is flat. Now g
0
g,sothisis
a complete metric on M . Thus .M; g
0
/ is isometrically equivalent to R
2
. Hence
.M; g/ is conformally equivalent to C.
On the other hand, the antipodal Gauss map
(7.47)
e
N W M ! S
2
;
e
N Dhrui
1
.ru; 1/;
is holomorphic; see Exercise 1 of 6. But the range of
e
N is contained in the lower
hemisphere of S
2
,soifwetakeS
2
D C [f1gwith the point at infinity identi-
fied with the “north pole” .0;0;1/, we see that
e
N yields a bounded holomorphic
function on M C. By Liouville’s theorem,
e
N must be constant. Thus M is a
flat plane in R
3
.
It turns out that Bernstein’s theorem extends to u W R
n
! R,forn 7,by
work of E. DeGiorgi, F. Almgren, and J. Simons, but not to n 8.
Exercises
1. If D
f
M.u/ is the differential operator given by (7.14)–(7.15), show that its principal
symbol satisfies
(7.48)
D
e
M.u/
.x; / D
1 Cjpj
2
jj
2
.p /
2
jj
2
;
where p Dru.x/.
2. Show that the formula (7.3)forM.f / is equivalent to
(7.49) M.f / D
X
j
@
j
hrf i
1
@
j
f
D div
hrf i
1
rf
:
3. Give a detailed demonstration of the estimate (7.26) on the slope of planes that can lie
above and below the graph of g over @O (assumed to have positive curvature), needed
for the proof of Proposition 7.5.(Hint: In case @O is the unit circle S
1
, consider the
cases g./ D cos
k
:)
4. Establish the formulas (7.42)–(7.44) for the Gauss curvature of a minimal surface.