kernel formalism. In section 13.2, we give a proof of the simplest version of the
Atiyah–Singer (AS) index theorem for a spin complex. Recently physicists have
found another proof of the theorem making use of supersymmetry. This proof is
outlined in sections 12.9 and 12.10. Interested readers should consult Alvarez-
Gaum´e (1983) and Friedan and Windey (1984, 1985) for further details.
The following corollary is a direct consequence of theorem 12.2.
Corollary 12.1. Let (M, E)
D
→ (M, F) be a two-term elliptic complex. The
index of D is given by
ind D = dim ker D − dim ker D
†
= (−1)
m(m+1)/2
M
(chE − chF)
Td(TM
)
e(TM)
vol
. (12.34)
12.3 The de Rham complex
Let M be an m-dimensional compact orientable manifold with no boundary. By
now we are familiar with the de Rham complex,
···
d
→
r−1
(M)
d
→
r
(M)
d
→
r+1
(M)
d
→··· (12.35)
where
r
(M) = (M, ∧
r
T
∗
M ). We complexified the forms so that we may
apply the AS index theorem. The exterior derivative satisfies d
2
= 0. To show
that (12.35) is an elliptic complex, we have to show that d is elliptic. To find the
symbol for d, we note that
σ(d,ξ)ω = d( f ˜s)
|
p
= d f ∧˜s + f d˜s|
p
= ξ ∧ ω
where p ∈ M,ω ∈
r
p
(M) , f (p) = 0, d f ( p) = ξ, ˜s ∈
r
(M) and
˜s( p) = ω; see (12.4). We find
σ(d,ξ) = ξ ∧ . (12.36)
This defines a map
r
(M) →
r+1
(M) and is non-singular if ξ = 0.
Thus, we have proved that d :
r
(M) →
r+1
(M) is elliptic and, hence,
(12.35) is an elliptic complex. Note, however, that the operator d :
k
(M) →
k+1
(M) is not Fredholm since ker d is infinite dimensional. To apply the index
theorem to this complex, we have to consider the de Rham cohomology group
H
r
(M) instead. The operator d is certainly Fredholm on this space.
Let us find the index theorem for this complex. We note that
dim
H
r
(M; ) = dim H
r
(M; ). Hence, the analytical index is
ind d =
m
r=0
(−1)
r
dim H
r
(M; )
=
(−1)
r
dim H
r
(M; ) = χ(M) (12.37)