σ
B σ B σ(B)
σ
B σ
σ B
σ
{a} [a, b) a, b ∈ IR
σ
(a, b)
σ
{a} =
∞
\
n=1
a −
1
n
, a +
1
n
[a, b) =
∞
\
n=1
a −
1
n
, b
Ω = [0, 1] σ σ(B)
Ω B = {(0, 1/3), (1/3, 1)}
σ
Ω ∈ σ(B) (0, 1/3) ∈ σ(B)
(1/3, 1) ∈ σ(B) (0, 1/3) ∪ (1/3, 1) ∈ σ(B)
∅ ∈ σ(B) {0, 1/3, 1} ∈ σ(B)
{0} ∪ [1/3, 1] ∈ σ(B) [0, 1/3] ∪ {1} ∈ σ(B)
σ B
σ(B) = {Ω, ∅, (0, 1/3), (1/3, 1), (0, 1/3) ∪ (1/3, 1),
{0, 1/3, 1}, {0} ∪ [1/3, 1], [0, 1/3] ∪ {1}}.
σ(B)
8 = 2
3
σ
(Ω, A) (Ω, F)
A σ F