1.2 Thermodynamics of Surfaces 35
Since for the system under consideration the partition function
˜
Z =
˜
Z (of the
bulk solution) ·
˜
Z (of the grain boundary solution), then
˜
Z = w
˜
Z
N
1
1
·
˜
Z
N
2
2
·w
x
·
˜
Z
x
N
x
·
˜
Z
x
N
x
−
N
x
U
1
kT
exp
−
N
x
U
2
kT
(1.135)
Here
˜
Z
1
and
˜
Z
2
are the partition functions for one atom of the first and second
components of the bulk solution;
˜
Z
x
and
˜
Z
x
are the same quantities for the
grain boundary solution; N
1
and N
2
and N
x
and N
x
are the numbers of atoms
of the first and second kind in the bulk and the grain boundary solution; w
and w
x
are the corresponding configurational (permutation) probabilities; U
1
and U
2
are the heats of transfer of atoms of the first and second kind from the
bulk solution into the grain boundary solution. The equilibrium distribution
of the impurities between the bulk and the grain boundary corresponds to
a minimum of the thermodynamic potential G of the system, that is to say
either the corresponding partial derivatives is equal to zero, in other words
the chemical potentials of the impurity atoms in both solutions are the same.
This minimum is usually found from the constancy condition either for the
number of solvent atoms or for the number of sites.
One can see that the statistical approach allows considerable freedom.
Firstly, it is associated with the choice of the constants for the determina-
tion of a chemical potential. Let us discuss this problem in greater detail.
Assume that g
1
and g
2
are the number of sites for the atoms of the first and
second kind in the bulk solution. If the atoms form a disordered substitutional
solid solution the values of g
1
and g
2
are indistinguishable; the total number
ofsitesinsuchasolutionisg = g
1
+ g
2
and it is just this quantity that ap-
pears in the statistical calculations for both atoms of the first and the second
kind. However, if the atoms form an interstitial solid solution (or an ordered
substitutional solid solution) the values g
1
and g
2
appear separately.
Let g
x
and g
x
be the number of sites for the atoms of the first and second
kind in the boundary solution. For the disordered substitutional solid solution
the sum g
x
+ g
x
= g
x
= const. appears as before in the calculations.
Let us postulate that the number of sites in the boundary solution is con-
stant, in other words
g
x
+ g
x
= g
x
= const. (1.136)
Notice that for the bulk solution this condition need not be satisfied. As an
example, if the components form a substitutional solution in the grain (in
the bulk), whereas at the grain boundary there is an interstitial one, a non-
compensated transfer of impurity atoms from the bulk to the grain boundary is
possible. Vacant lattice points should appear in this instance. Let us consider,
however, an equilibrium concentration of vacancies in the bulk (N
v
= N
e
v
).
Then the vacant lattice points will disappear and g = const. (We assume,
also, that the value of N
e
v
does not depend on the content of the impurities
in the solution.)
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