523.5
Use of the Macroscopic Balances to Solve Steady-State Problems
751
By substituting numerical values into Eqs. 23.5-54 and 55, we obtain (see Problem 23A.1) T2
=
920K and
v,
=
1726 ft/s. It may be seen that this treatment is very similar to that presented in
Example 15.5-4. It is also subject to the restriction that the throat velocity must be subsonic;
that is, the pressure in the nozzle throat cannot fall below that fraction of
p,
required to pro-
duce sonic velocity at the throat (see Eq. 15B.6-2).
If
the ambient pressure falls below this criti-
cal value of p,, the throat pressure will remain at the critical value, and there will be a shock
wave beyond the nozzle exit.
Approximation
0:
Assumption of ve
y
rapid reaction. We may proceed here as in part
(a), except that the mole fractions x, must now be considered functions of the temperature de-
fined by the equilibrium relation
and the stoichiometric relations
The quantity
KJT)
in Eq. 23.5-56 is the known equilibrium constant for the reaction. It may be
considered as a function only of temperature, because of the assumed ideal gas behavior and
because the number of moles present is not affected by the chemical reaction. Equations 23.5-
57 and 58 follow from the stoichiometry of the reaction and the composition of the gas origi-
nally placed
in
the tank.
The expression for the final temperature is now considerably more complicated. For this
reaction, where C.,x,M, is constant, Eqs. 23.5-49 and 50 may be combined to give
where, with the heat capacities approximated as constar~ts,
In general, the integral in Eq. 23.5-60 must be evaluated numerically, since the x, and the
dx,/dT are all complicated functions of temperature governed by Eqs. 23.5-56 to 59. Once T2
has been determined from Eq. 23.5-61, however,
v,
may be obtained by use of Eqs. 23.548
and 51. By substituting numerical values into these expressions, we obtain (see Problem
23B.2) T2
=
937K and
v2
=
1752 ft /s.
We find, then, that both the exit temperature and the velocity from the nozzle are greater
when chemical equilibrium is maintained throughout the expansion. The reason for this is
that the equilibrium shifts with decreasing temperature in such a way as to release heat of re-
action to the system. Such a release of energy will occur with decreasing temperature in any
system at chemical equilibrium, regardless of the reactions involved. This is one consequence
of the famous rule of Le Chatelier. In this case, the reaction is endothermic as written and the
equilibrium constant decreases with falling temperature. As a result,
CO
and
H,O
are par-
tially reconverted to
H,
and C02 on expansion, with a corresponding release of energy.
It is interesting that in rocket engines the exhaust velocity, hence the engine thrust, are
also increased if rapid equilibration can be obtained, even though the combustion reactions
are strongly exothermic. The reason for this is that the equilibrium constants for these reac-
tions increase with falling temperature so that the heat of reaction is again released on expan-
sion. This principle has been suggested as a method for improving the thrust of rocket
engines. The increase in thrust potentially obtainable in this way is quite large.
This example was chosen for its simplicity. Note in particular that if a change in the num-
ber of moles accompanies the chemical reaction, then the equilibrium constant, and hence the
enthalpy, are functions of the pressure. In this case, which is quite common, the variables
p