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48 Asymptotic analysis of wave equations
where A(x/t)/
√
t is the decaying in time, slowly varying, complex amplitude.
This decay rate, O(1/
√
t), is slow, especially when compared to those cases
when the solution decays exponentially or as O(1/t
n
)forn large. Note that
dimensionally, ω
corresponds to a speed. Stationary phase has shown that the
leading-order contribution comes from a region moving with speed ω
, which
is termed the group velocity. This is the velocity of a slowly varying packet of
waves. We will see later that this is also the speed at which energy propagates.
Example 3.1 Linear KdV equation: u
t
+ u
xxx
= 0. The dispersion relation is
ω = −k
3
and so φ(k) = kx/t + k
3
. Thus, the stationary points, satisfying (3.6),
occur at k
0
= ±
√
−x/(3t) so long as x/t < 0. Note that we might expect
something interesting to happen as x/t → 0, since φ
(k) vanishes there and
implies a higher-order stationary point. We also expect different behavior when
x/t > 0 since k
0
becomes imaginary there.
Example 3.2 Free-particle Schr
¨
odinger equation: iψ
t
+ ψ
xx
= 0, |x| < ∞,
ψ(x, 0) = f (x), and ψ → 0as|x|→∞. This is a fundamental equation in quan-
tum mechanics. The wavefunction, ψ, has the interpretation that |ψ(x, t)|
2
dx is
the probability of finding a particle in dx, a small region about x at time t.
The dispersion relation ω = k
2
shows that the stationary point satisfying (3.6)
occurs at k
0
= x/(2t).
3.2 Linear free Schr
¨
odinger equation
Now we will consider a specific example of the method of stationary phase as
applied to the linear free Schr
¨
odinger equation
iu
t
+ u
xx
= 0. (3.9)
First assume a wave solution of the form u
s
= e
i(kx−ω(k)t)
, substitute it into the
equation and derive the dispersion relation
ω(k) = k
2
.
Notice that ω is real and ω
(k) = 2 0 and hence solutions to (3.9) are in the
dispersive wave regime. Thus the solution, via Fourier transforms, is
u(x, t) =
1
2π
ˆu
0
(k)e
i(kx−k
2
t)
dk,
where ˆu
0
(k) is the Fourier transform of the initial condition u(x, 0) = u
0
(x). As
before, to apply the method of stationary phase, we rewrite the exponential in
the Fourier integral the following way