6.6 Further exercises and problems 229
where L, T are respectively the spaces of functions representable as infinite sums
of the longitudinal and transverse eigenfunctions, and N is the finite-dimensional
space of harmonic (null-space) eigenfunctions.
Complete sets of vector eigenfunctions for the interior of a rectangular box, and for each
of the four sets of boundary conditions we have considered, can be found in Morse and
Feshbach §13.1.
Problem 6.19: Hodge–Weyl and Helmholtz–Hodge. In this exercise we consider the
problem of what classes of vector-valued functions can be expanded in terms of the
various families of eigenfunctions of the previous problem. It is tempting (but wrong)
to think that we are restricted to expanding functions that obey the same boundary
conditions as the eigenfunctions themselves. Thus, we might erroniously expect that
the E
n
are good only for expanding functions whose divergence vanishes and have
vanishing tangential boundary components, or that the η
n
can expand out only curl-free
vector fields with vanishing normal boundary component. That this supposition can be
false was exposed in section 2.2.3, where we showed that functions that are zero at the
endpoints of an interval can be used to expand out functions that are not zero there.
The key point is that each of our four families of u
n
constitute a complete orthonormal
set in L
2
vec
(), and can therefore be used expand any vector field. As a consequence,
the infinite sum
,
a
n
E
n
∈ T can, for example, represent any vector-valued function
u ∈ L
2
vec
() provided only that u possesses no component lying either in the subspace
L of the longitudinal eigenfunctions
n
, or in the nullspace N .
(a) Let T =E
n
be space of functions representable as infinite sums of the E
n
. Show
that
E
n
⊥
={u : curl u = 0 within , n × u = 0on∂}.
Similarly show that
n
⊥
={u : div u = 0 within , no condition on ∂},
H
n
⊥
={u : curl u = 0 within , no condition on ∂},
η
n
⊥
={u : div u = 0 within , n · u = 0on∂},
B
n
⊥
={u : curl u = 0 within , no condition on ∂}.
β
n
⊥
={u : div u = 0 within , no condition on ∂},
(b) Use the results of part (a) and the Helmholtz–Hodge decomposition to show that
E
n
={u ∈ L
2
vec
() : u = curl w, no condition on w on ∂}.
n
={u ∈ L
2
vec
() : u =∇φ, where φ = 0on∂},
H
n
={u ∈ L
2
vec
() : u = curl w, where n × w = 0on∂},
η
n
={u ∈ L
2
vec
() : u =∇φ, no condition on φ on ∂},