Радецкий А.М., Горшкова В.П. Решение контрольных и самостоятельных работ по химии за 9 класс
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Z
FeCl
3
→
Fe
3+
+3Cl
-
[
K
2
SO
4
→
2K
+
+SO
−
\
Ba(NO
3
)
2
→
Ba
2+
+2NO
−
]
H
3
PO
4
→
3H
+
+PO
−
^
NaOH
→
Na
+
+OH
-
Z
H
2
SO
4
+BaCl
2
→
BaSO
4
↓
+2HCl
Ba
2+
+SO
−
→
BaSO
4
↓
[
3KOH+H
3
PO
4
→
K
3
PO
4
+3H
2
O
OH
-
+H
+
→
H
2
O
\
Na
2
CO
3
+Pb(NO
3
)
2
→
2NaNO
3
+PbCO
3
↓
Pb
2+
+CO
−
→
PbCO
3
↓
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Z
Ca(OH)
2
→
Ca
2+
+2OH
-
[
CuCl
2
→
Cu
2+
+2Cl
-
\
H
2
SO
4
→
2H
+
+SO
−
]
Fe
2
(SO
4
)
3
→
2Fe
3+
+3SO
−
^
KNO
3
→
K
+
+NO
−
Z
HCl+AgNO
3
→
AgCl
↓
+HNO
3
Cl
-
+Ag
+
→
AgCl
↓
[
BaCl
2
+CuSO
4
→
BaSO
4
↓
+CuCl
2
Ba
2+
+SO
−
→
BaSO
4
↓
\
Ca(OH)
2
+2HNO
3
→
Ca(NO
3
)
2
+2H
2
O
OH
-
+H
+
→
H
2
O
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1.
Z
AlCl
3
→
Al
3+
+3Cl
-
6
[
K
3
PO
4
→
3K
+
+PO
−
\
HNO
3
→
H
+
+NO
−
]
Na
2
SO
4
→
2Na
+
+SO
−
^
MgCl
2
→
Mg
+
+2Cl
-
Z
Na
2
CO
3
+CaCl
2
→
2NaCl+CaCO
3
↓
CO
−
+Ca
2+
→
CaCO
3
↓
[
Ba(OH)
2
+2HCl
→
BaCl
2
+2H
2
O
OH
-
+H
+
→
H
2
O
\
H
2
SO
4
+Ba(NO
3
)
2
→
BaSO
4
↓
+2HNO
3
SO
−
+Ba
2+
→
BaSO
4
↓
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1.
Z
Cu(NO
3
)
2
→
Cu
2+
+2NO
−
[
HCl
→
H
+
+Cl
-
\
Al
2
(SO
4
)
3
→
2Al
3+
+3SO
−
]
Ba(OH)
2
→
Ba
2+
+2OH
-
^
ZnSO
4
→
Zn
2+
+SO
−
Z
LiOH+HNO
3
→
LiNO
3
+H
2
O
OH
-
+H
+
→
H
2
O
[
Cu(NO
3
)
2
+2NaOH
→
Cu(OH)
2
↓
+2NaNO
3
Cu
2+
+2OH
-
→
Cu(OH)
2
↓
\
3K
2
CO
3
+2H
3
PO
4
→
2K
3
PO
4
+3CO
2
↑
+3H
2
O
CO
−
+2H
+
→
CO
2
+H
2
O
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Z
3AgNO
3
+K
3
PO
4
→
Ag
3
PO
4
↓
+3KNO
3
3Ag
+
+PO
−
→
Ag
3
PO
4
↓
[
CuSO
4
+2NaOH
→
Cu(OH)
2
↓
+Na
2
SO
4
Cu
2+
+2OH
-
→
Cu(OH)
2
↓
]
BaCl
2
+K
2
SO
4
→
BaSO
4
↓
+2KCl
Ba
2+
+SO
−
→
BaSO
4
↓
2. Na
2
CO
3
+H
2
O
→
←
NaOH+NaHCO
3
7
CO
−
+H
2
O
→
←
OH
-
+HCO
−
NaHCO
3
+H
2
O
→
←
NaOH+H
2
CO
3
HCO
−
+H
2
O
→
←
OH
-
+H
2
CO
3
Cu(NO
3
)
2
+H
2
O
→
←
Cu(OH)NO
3
+HNO
3
Cu
2+
+H
2
O
→
←
CuOH
+
+H
+
Cu(OH)NO
3
+H
2
O
→
←
Cu(OH)
2
+HNO
3
&XHG
+
+H
2
O
→
←
Cu(OH)
2
+H
+
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Z
Na
2
CO
3
+2HNO
3
→
2NaNO
3
+H
2
O+CO
2
CO
−
+2H
+
→
CO
2
+H
2
O
\
2HCl+Ba(OH)
2
→
BaCl
2
+2H
2
O
H
+
+OH
-
→
H
2
O
]
3NaOH+H
3
PO
4
→
Na
3
PO
4
+3H
2
O
OH
-
+H
+
→
H
2
O
2. Na
2
S+H
2
O
→
←
NaOH+NaHS
S
2-
+H
2
O
→
←
OH
-
+HS
-
NaHS+H
2
O
→
←
NaOH+H
2
S
HS
-
+H
2
O
→
←
OH
-
+H
2
S
FeCl
3
+H
2
O
→
←
Fe(OH)Cl
2
+HCl
Fe
3+
+H
2
O
→
←
FeOH
2+
+H
+
Fe(OH)Cl
2
+H
2
O
→
←
Fe(OH)
2
Cl+HCl
FeOH
2+
+H
2
O
→
←
Fe(OH)
+
+H
+
Fe(OH)
2
Cl+H
2
O
→
←
Fe(OH)
3
+HCl
Fe(OH)
+
+H
2
O
→
←
Fe(OH)
3
+H
+
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Z
FeCl
3
+3NaOH
→
3NaCl+Fe(OH)
3
↓
Fe
3+
+3OH
-
→
Fe(OH)
3
↓
\
Ba(NO
3
)
2
+Na
2
CO
3
→
BaCO
3
↓
+2NaNO
3
Ba
2+
+CO
−
→
BaCO
3
↓
]
Al
2
(SO
4
)
2
+2K
3
PO
4
→
2AlPO
4
↓
+3K
2
SO
4
8
Al
3+
+PO
−
→
AlPO
4
↓
2. Zn(NO
3
)
2
+H
2
O
→
←
Zn(OH)NO
3
+HNO
3
Zn
2+
+H
2
O
→
←
ZnOH
+
+H
+
Zn(OH)NO
3
+H
2
O
→
←
Zn(OH)
2
+HNO
3
ZnOH
+
+H
2
O
→
←
Zn(OH)
2
+H
+
K
2
CO
3
+H
2
O
→
←
KOH+KHCO
3
CO
−
+H
2
O
→
←
OH
-
+HCO
−
KHCO
3
+H
2
O
→
←
KOH+H
2
CO
3
HCO
−
+H
2
O
→
←
OH
-
+H
2
CO
3
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Z
K
2
CO
3
+2HCl
→
2KCl+CO
2
+H
2
O
CO
−
+2H
+
→
H
2
O+CO
2
[
Ca(OH)
2
+2HNO
3
→
Ca(NO
3
)
2
+2H
2
O
OH
-
+H
+
→
H
2
O
\
2NaOH+H
2
SO
4
→
Na
2
SO
4
+2H
2
O
OH
-
+H
+
→
H
2
O
2. AlCl
3
+H
2
O
→
←
Al(OH)Cl
2
+HCl
Al
3+
+H
2
O
→
←
AlOH
2+
+H
+
Al(OH)Cl
2
+H
2
O
→
←
Al(OH)
2
Cl+HCl
AlOH
2+
+H
2
O
→
←
Al(OH)
+
+H
+
Al(OH)
2
Cl+H
2
O
→
←
Al(OH)
3
+HCl
Al(OH)
+
+H
2
O
→
←
Al(OH)
3
+H
+
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1. Ba(OH)
2
+Na
2
SO
4
→
BaSO
4
↓
+2NaOH
Ba
2+
+SO
−
→
BaSO
4
↓
Ba(OH)
2
+CuCl
2
→
Cu(OH)
2
↓
+BaCl
2
2OH
-
+Cu
2+
→
Cu(OH)
2
↓
Ba(OH)
2
+2HNO
3
→
Ba(NO
3
)
2
+2H
2
O
9
OH
-
+H
+
→
H
2
O
Ba(OH)
2
+CO
2
→
BaCO
3
↓
+H
2
O
2.
)H62
)
H
&
O
)
H
1
2
Z
[
Z
FeSO
4
+BaCl
2
→
FeCl
2
+BaSO
4
↓
SO
−
+Ba
2+
→
BaSO
4
↓
[
FeSO
4
+Ba(NO
3
)
2
→
Fe(NO
3
)
2
+BaSO
4
↓
Ba
2+
+SO
−
→
BaSO
4
↓
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1. H
2
SO
4
+2NaOH
→
Na
2
SO
4
+2H
2
O
H
+
+OH
-
→
H
2
O
H
2
SO
4
+Zn
→
ZnSO
4
+H
2
↑
2H
+
+Zn
→
Zn
2+
+H
2
H
2
SO
4
+BaCl
2
→
BaSO
4
↓
+HCl
SO
2
4
−
+Ba
2+
→
BaSO
4
↓
H
2
SO
4
+CuO
→
CuSO
4
+H
2
O
2H
+
+CuO
→
Cu
2+
+H
2
O
Na
2
SO
4
+Ba(OH)
2
→
BaSO
4
↓
+2NaOH
SO
−
+Ba
2+
→
BaSO
4
↓
NaOH+HCl
→
NaCl+H
2
O
OH
-
+H
+
→
H
2
O
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1. CuCl
2
+2AgNO
3
→
2AgCl
↓
+Cu(NO
3
)
2
Cl
-
+Ag
+
→
AgCl
↓
CuCl
2
+Fe
→
FeCl
2
+Cu
Cu
2+
+Fe
→
Fe
2+
+Cu
CuCl
2
+2KOH
→
Cu(OH)
2
↓
+2KCl
Cu
2+
+2OH
-
→
Cu(OH)
2
↓
Z
H
2
SO
4
+Ba(NO
3
)
2
→
BaSO
4
↓
+2HNO
3
[
KCl+AgNO
3
→
AgCl
↓
+KNO
3
Cl
-
+Ag
+
→
AgCl
↓
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1. 2HCl+Ca(OH)
2
→
CaCl
2
+2H
2
O
10
H
+
+OH
-
→
H
2
O
6HCl+2Al
→
2AlCl
3
+3H
2
↑
6H
+
+2Al
→
2Al
3+
+3H
2
2HCl+Na
2
CO
3
→
2NaCl+H
2
O+CO
2
2H
+
+CO
−
→
H
2
O+CO
2
2HCl+MgO
→
MgCl
2
+H
2
O
2H
+
+MgO
→
Mg
2
+
+H
2
O
2. MgO+H
2
SO
4
→
MgSO
4
+H
2
O
MgO+2H
+
→
Mg
2
+
+H
2
O
Mg(OH)
2
+H
2
SO
4
→
MgSO
4
+2H
2
O
Mg(OH)
2
+2H
+
→
Mg
2+
+2H
2
O
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260
]]
32 2 4
Ba(NO ) +K SO
→
BaSO
4
↓
+2KNO
3
n(Ba(NO
3
)
2
)=
32
32
m(Ba(NO ) )
260
M(Ba(NO ) ) 261
=
=0,996
fhev
n(K
2
SO
4
)=
24
24
m(K SO ) 220
M(K SO ) 174
=
=1
fhev
Ld
K
2
SO
4
gZoh^blky\ba[uld_lhjZkq_l\_^_fih
Ba(NO
3
)
2
260
]
32
261
]
Ba(NO )
+K
2
SO
4
→
o]
4
233
]
BaSO
↓
+2KNO
3
o
=
o
=
≈
⋅
232,11
]
Hl\_l
m(BaSO
4
)=
]
2.
42,6
]
16
]
33
Al(NO ) +3NaOH
→
Al(OH)
3
↓
+3NaNO
3
n(Al(NO
3
)
3
)=
33
33
m(Al(NO ) )
42,6
M(Al(NO ) ) 213
=
=0
fhev
n(NaOH)=
m(NaOH) 16
M(NaOH) 40
=
=0,4
fhev
Ld
NaOH
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