dimensions, we have ε
ij
, with ε
12
= −ε
21
= 1, ε
11
= ε
22
= 0. It is easy to see, simply by
checking all the possible index assignments, that
ε
ij
ε
kℓ
= δ
ik
δ
jℓ
− δ
iℓ
δ
jk
. (7.57)
(Try it for a few choices, such as i = 1, j = 2, k = 1, ℓ = 2, etc.)
In three dimensions, the analogous product rule involves 6 terms rather than 2 on the
right-hand-side:
ε
ijk
ε
ℓmn
= δ
iℓ
δ
jm
δ
kn
+δ
in
δ
jℓ
δ
km
+δ
im
δ
jn
δ
kℓ
−δ
iℓ
δ
jn
δ
km
−δ
im
δ
jℓ
δ
kn
−δ
in
δ
jm
δ
kℓ
. (7.58)
Looking at this, one can see the pattern. The first term on the right-hand side has the
product of a Kronecker delta linking the first indices on the two epsilon tensors, a Kr on ecker
delta linking the second indices on the two epsilon tensors, and a Kronecker delta linking
the last indices on the two epsilon tensors. Then, there are 5 more terms, which correspond
to permuting around th e ℓ, m and n indices, with a plus sign for an even permutation, and
a minus sign for an odd permutation. There are in total 3! possible permutations, hence
the six terms on the r ight-hand side. The need for this permutation antisymmetry in the
expression on the right-hand side is obvious, since we k now that it is an antisymmetry
of the left-hand side. Note also that although as stated above, the implementation of
the permutation antisymmetry of ℓ, m an d n might seem to have been favoured over the
permutation antisymmetry of i, j, k, in fact everything is perfectly democratic. Having
enforced the antisymmetry in ℓ, m and n on the right-hand side, it implies (as can easily
be seen by inspection) an antisymmetry in i, j and k as well.
It is not hard to prove (7.58), again by looking at all the possible index assignments
for i, j, k, ℓ, m and n. This is not as daunting a task as it might sound , because of the
antisymmetries discussed ab ove. In fact, if one thinks about it, there are very few cases th at
need to be checked explicitly; the rest all follow by invoking the permutation symmetries.
The general expression for the product of two epsilon tensors in n d imen s ions will involve
n! s ums of products of Kronecker deltas on the right-hand side:
ε
i
1
···i
n
ε
j
1
···j
n
= δ
i
1
j
1
···δ
i
n
j
n
+ even perms − odd perms . (7.59)
7.4.3 Three-dimensional vector identities
A very useful consequence of (7.58) in 3 dimensions arises if we set k = n (which means,
of course, that this repeated index is then summed over 1, 2 and 3.) Bearing in mind
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