250 9. Sobolev Spaces and L
2
Regularity Theory
the spirit of that definition, we thus start with the model situation of the
domain
R
d
+
:=
(x
1
,...,x
d
) ∈ R
d
,x
d
> 0
.
If now u ∈ C
k
(R
d
+
), we define an extension via
E
0
u(x):=
u(x)forx
d
≥ 0,
k
j=1
a
j
u(x
1
,...,x
d−1
, −
1
j
x
d
)forx
d
< 0,
(9.4.1)
where the a
j
are chosen such that
k
j=1
a
j
−
1
j
ν
=1 forν =0,...,k−1. (9.4.2)
One readily verifies that the system (9.4.2) is uniquely solvable for the a
j
(the
determinant of this system is a Vandermonde determinant that is nonzero).
One moreover verifies, and this of course is the reason for the choice of the a
j
,
that the derivatives of E
0
u up to order k −1 coincide with the corresponding
ones of u on the hyperplane
x
d
=0
, and that the derivatives of order k are
bounded whenever those of u are. Thus
E
0
u ∈ C
k−1,1
(R
d
), (9.4.3)
where C
l,1
(Ω)isdefinedasthespaceofl-times continuously differentiable
functions on Ω whose lth derivatives are Lipschitz continuous, i.e.,
sup
x∈Ω
|v(x) − v(x
0
)|
|x − x
0
|
< ∞
for any such derivative v and x
0
∈ Ω (see also Definition 11.1.1 below).
If now Ω is a domain of class C
k
in the sense of Definition 9.3.1, and if
u ∈ C
k
(
¯
Ω) (see Definition 9.3.2), we may locally straighten out the boundary
with a C
k
-diffeomorphism φ
−1
, extend the functions u ◦ φ
−1
with the above
operator E
0
, and then take E
0
(u ◦ φ
−1
) ◦ φ. This function then defines a
local extension of class C
k−1,1
of u across ∂Ω. In order to obtain a global
extension, we simply patch these local extensions together with the help of
a partition of unity. This is easy, and the reader may know this construction
already, but for completeness, we present the details. We assume that Ω is a
bounded domain of class C
k
.Thus,∂Ω is compact, and so it may be covered
by finitely many sets of the type Ω∩
˚
B(x
0
,r) on which a local diffeomorphism
with the properties specified in Definition 9.3.1 exists.
We call these sets Ω
ν
, ν =1,...,n, and the corresponding diffeomor-
phisms φ
ν
. In addition, we may find an open set Ω
0
⊂ Ω,with∂Ω ∩
¯
Ω
0
= ∅,
so that