44 1 Continuous-Path Random Processes: Mathematical Prerequisites
Theorem 1.5.4.3 Assume that f and g satisfy the Lipschitz condition, for
a constant K>0, which does not depend on t,
f(t, w) − f (t, w
) + g(t, w) − g(t, w
)≤K sup
s≤t
w(s) − w
(s).
Then, e(f,g) admits a unique strong solution, up to indistinguishability.
See [RY], Chapter IX for a proof. The following theorem, due to Yamada and
Watanabe (see also [RY] Chapter IX, Theorem 1.7) establishes a hierarchy
between different uniqueness properties.
Theorem 1.5.4.4 If pathwise uniqueness holds for e(f,g), then uniqueness
in law holds and the solution is strong.
Example 1.5.4.5 Pathwise uniqueness is strictly stronger than uniqueness
in law. For example, in the one-dimensional case, let σ(x)=sgn(x), with
sgn(0) = −1. Any solution (X, B)ofe(0,σ) (meaning that g(t, X
)=σ(X
t
))
starting from 0 is a standard BM, thus uniqueness in law holds. On the other
hand, if β is a BM, and B
t
=
t
0
sgn(β
s
)dβ
s
,then(β,B)and(−β,B)aretwo
solutions of e(0,σ) (indeed, dB
t
= σ(β
t
)dβ
t
is equivalent to dβ
t
= σ(β
t
)dB
t
),
and pathwise uniqueness does not hold. If (X, B) is any solution of e(0,σ),
then B
t
=
t
0
sgn(X
s
)dX
s
,andF
B
= F
|X|
which establishes that any solution
is strictly weak (see Comments 4.1.7.9 and Subsection 5.8.2 for the
study of the filtrations).
A simple case is the following:
Theorem 1.5.4.6 Let b :[0,T] × R
d
→ R
d
and σ :[0,T] × R
d
→ R
d×n
be
Borel functions satisfying
b(t, x) + σ(t, x)≤C(1 + x) ,x∈ R
d
,t∈ [0,T],
b(t, x) − b(t, y) + σ(t, x) − σ(t, y)≤Cx − y,x,y ∈ R
d
,t∈ [0,T]
and let X
0
be a square integrable r.v. independent of the n-dimensional
Brownian motion B. Then, the stochastic differential equation (SDE)
dX
t
= b(t, X
t
)dt + σ(t, X
t
)dB
t
,t≤ T, X
0
= x
has a unique continuous strong solution, up to indistinguishability. Moreover,
this process is a strong (inhomogeneous) Markov process.
Sketch of the Proof: The proof relies on Picard’s iteration procedure.
In a first step, one considers the mapping Z → K(Z)where
(K(Z))
t
= x +
t
0
b(s, Z
s
)ds +
t
0
σ(s, Z
s
)dB
s
,
and one defines a sequence (X
n
)
∞
n=0
of processes by setting X
0
= x,and
X
n
= K(X
n−1
). Then, one proves that