January 26, 2004 16:26 WSPC/Book Trim Size for 9in x 6in b ook2
Ideal Quantum Gases 103
do not depend on angles, the space angle as well as other normalization
constants drop out and we obtain from Eq. (6.62) :
1=(2s +1)z
k
B
T
E
0D
D/2
J
±
D
(z)
J
D
(0)
, (6.66)
where
J
±
D
(z)=
∞
0
dk k
D−1
1
e
k
2
± z
and J
D
(0) = Γ(D/2). (6.67)
The gamma function is given for D =3, 2, and 1 by the values Γ(3/2) =
π/2, Γ(1) = 1, Γ(1/2) =
√
π, respectively. In general, the integral J
±
D
(z)
has to be evaluated numerically for the three- and one-dimensional cases.
We obtain an analytical result only in two dimensions (see Sec. 6-1.2 and
6-2.2):
J
±
2
(z)=∓
1
z
ln(1 ± z) . (6.68)
As before, the limiting case of Boltzmann distributions is obtained from
Eq. (6.66) if we approximate the factor J
±
D
(z)/J
D
(0) 1.
In order to compare the particle statistics with each other for different
dimensionalities, we rewrite Eq. (6.66) as
k
B
T
E
0D
=
(2s +1)z
J
±
D
(z)
J
D
(0)
−2/D
. (6.69)
The ratio of the thermal energy k
B
T to the zero-point energy E
0D
is a
measure of the degeneracy of the ideal quantum gas. For ratios larger than
one, quantum effects can be neglected. On the other hand, quantum effects
dominate over thermal ones if k
B
T/E
0D
is smaller than one. In Fig. 6.3,
we plot k
B
T/E
0D
logarithmically versus the ratio of the chemical potential
to the thermal energy µβ. For better comparison, we have put s =0for
all cases. In such a plot, we obtain a straight line with a slope of −2/D for
the Boltzmann limit, as can be seen by taking the logarithm of the RHS of
Eq. (6.69). For Bosons, the figure shows clearly that for D =3the chemical
potential becomes zero in the vicinity of k
B
T E
0D
, whereas it approaches
zero only asymptotically for D =2, 1. This shows again the absence of a
Bose–Einstein condensation in dimensions lower than three. For Fermions,
the chemical potential becomes positive and converges to the Fermi energy
as the degeneracy parameter k
B
T/E
0D
→ 0.