
Combinatorial
Theory
strongest team, plays
A,
the weakest? Work
it out yourself. Team
A
is the winner by
five to four! Which, then, is the strongest
team? The paradox brings out the weak-
ness of round-robin
play in deciding the
relative strengths of teams. Moser has
analyzed many paradoxes of this sort, of
which this is one of the simplest. The para-
dox also holds if teams
A,
B,
and
C
are the
columns of the
Lo Shu
instead of the rows.
Similar paradoxes, Moser points out,
arise in voting. For example, assume that
one person's preference for three candi-
dates is in the order
A,
B,
C.
A
second per-
son prefers
B,
C,
A
and a third prefers
C,
A,
B.
It is easy to see that a majority of the
three voters prefers
A
to
B,
a majority pre-
fers
B
to
C,
and (confusingly) a majority
also prefers
C
to
A!
This simple paradox
was apparently first discussed in 1785 by
the French mathematician, the Marquis de
Cordorcet, and first rediscovered
by
Lewis
Carroll who published several remarkable
on voting procedures. The para-
dox was independently rediscovered later
by many others. (For a history of the para-
dox, and a listing of important recent works
in which its implications for group decision
theory are analyzed, see "Voting and the
Summation of Preferences,"
by William
H.
Riker,
The Arnericun Political Science
Review,
December, 1961. On the applica-
tion of the
~aradox to the scores of corn-
peting teams, see
"A
Paradox in the Scoring
of Competing Teams," by
E.
V. Huntington,
Science,
Vol. 88, 1938, pages 287-288.)
The arrangement
of
elements in square
and rectangular matrices provides a large
portion of modern cornbinatorial problems,
many of which have found useful
applica-
tions in the field of experimental design. In
Latin squares the elements are so arranged
that an element of one type appears no
more than once in each row and column.
Here is a pretty combinatorial problem
along such lines that is not difficult but
conceals a tricky twist that
may escape
many readers:
Suppose you have on hand an unlimited
supply of postage stamps with values of
one, two, three, four, and five cents (that
is, an unlimited supply of each value). You
wish
to
arrange as
many
stamps as possible
on a four-by-four square matrix so that no
two stamps of the same value will be in the
same row, column, or
any diagonal (not
just the two main diagonals). In other
words, if you place a chess queen on any
stamp in the square and make a single
move in any direction, the queen's path
will not touch two stamps of like value.
There is one further proviso: the total value
of the stamps in the square must be as large
as possible. What is the
maximum? No cell
may contain more than one stamp, but one
or more cells may, if you wish, remain
empty.
Addendum
After my publication of the magic hexagon,
John
R.
A.
Cooper called my attention to a
prior publication without commentary by
Tom
Vickers in
The hrlutlzernuticul Gazette,
December, 1958, page 291. So far as
I
know,