426
Chapter
27.
Triangle Inequalities
can
be reformulated as the problem:
max
x E
RMET;+l
x E {O,l}En+l.
Hence, if one wishes to solve
the
max-cut problem using linear programming
techniques, one faces
the
problem of finding what are
the
additional constraints
needed to be added to the above formulation
in
order
to
eliminate
the
integrality
condition.
This
is
the
question of finding the facet defining inequalities for
the
cut polytope, which forms
the
main topic of
Part
V.
27.2.2
Volume
of
the
Rooted
Semimetric
Polytope
Computing
the
exact volume of a polytope is,
in
general, a difficult problem.
A nice property of the rooted triangle inequalities is
that
one
can
compute ex-
actly
the
volume of
the
rooted semimetric polytope. This was done by Ko, Lee
and
Steingrimsson
[1997]
who showed, using the switching symmetries, how
the
problem
can
be
reduced to
that
of computing
the
volume of
an
order polytope.
Theorem 27.2.2.
Set
d
:=
(nil). Then, the d-dimensional volume
of
the rooted
semimetric
polytope
RMET;+l
is equal to
o
n!
n
vol RMETn+l = (2n)!2
The d-dimensional volume
of
its image
under
the covariance mapping is
vol
e(RMET;+I)
=
(nl),2
2n
-
d
.
2n.
Proof. To simplify the notation, set Qn
:=
e(RMET;+1)'
In
a first step, let us
compute
the
d-dimensional volume of Qn.
The
polytope Qn is defined by the
rooted
triangle inequalities, namely,
(i)
Pij
~
0,
Pij
~
Pii,
Pij
~
Pjj,
(ii)
Pii
+
Pjj
~
1 +
Pij
for all 1
~
i < j
~
n. For a E
{O,
I}
n,
set
G
a
:=
{p
E Qn I ai
~Pii
~
a.;
+
~
(i 1,
...
,n)}.
Then,
for distinct
a,
b E
{O,
l}n,
the d-dimensional volume of G
a
n
Gb
is equal
to
o (as G
n
n
Gb
has dimension < d). Clearly, Qn is the union
of
the polytopes G
n
(for a E
{O,l}n).
Hence,
vol
Qn L vol
Ga.
aE{O,l }n