298 The Cauchy problem for quasilinear systems
Hence (u
k
)
k∈N
will be a Cauchy sequence in C ([0,T]; L
2
) provided that the series
k
g
k+1
− g
k
2
L
2
is convergent. The estimate in (10.1.6) shows that this holds true for ε
k
=2
−k
ε,
for instance. With this choice, the sequence (u
k
)
k∈N
has a limit u in C ([0,T]; L
2
).
It remains to prove additional regularity on u. (The method will generalize the
proof of the continuity with values in H
1
of the solution in Theorem 2.9.)
Regularity and uniqueness Since (u
k
(t))
k∈N
is bounded in H
s
(see
(10.1.16)) and convergent in L
2
(for t ≤ T ), the limit u(t)mustbeinH
s
by
weak compactness of bounded balls in H
s
and uniqueness of the limit in the
sense of distributions. Furthermore, by L
2
–H
s
interpolation, u
k
is found to
converge in C ([0,T]; H
s
) for all s
∈ (0,s). In particular, we can choose s
greater
than 1 + d/2 (like s). Standard Sobolev embeddings then imply the convergence
holds in C ([0,T]; C
1
b
(R
d
)). Thus we can pass to the limit in the iteration scheme
(10.1.5), which shows that ∂
t
u
k
tends to ∂
t
u in C ([0,T]; C
b
(R
d
)) and the limit u
is a C
1
solution of (10.1.3). The initial condition is trivially satisfied, by passing
to the limit in the initial condition for u
k
. It is not difficult to show that the C
1
solution constructed by the iteration scheme (10.1.5) is the only one satisfying
(10.1.8) in the time interval [0,T]. As a matter of fact, the L
2
norm of the
difference between two solutions u and v can be estimated similarly as in the low-
norm calculation on u
k+1
− u
k
. (We can even show the uniqueness of classical
solutions in the wider class of entropy solutions, see [46] and Section 10.2 below.)
We already know that u belongs to C ([0,T]; H
s
) for all s
<s. In fact, we can
show that u belongs to C ([0,T]; H
s
) (which automatically implies that u belongs
to C
1
([0,T]; H
s−1
) by the equation in (10.1.3)). The proof is not obvious though.
As a first step, we can check that u
k
(t) converges uniformly on [0,T]inH
s
w
,
the space H
s
equipped with the weak topology. We just take any φ in H
−s
,
choose ψ in the dense subspace H
−s
(for s
<s) close enough to φ,andmakea
standard splitting. Using the estimates in (10.1.16), we get
sup
t∈[0,T ]
|φ, (u
k
−u)(t)
H
−s
,H
s
|≤Cφ − ψ
H
−s
+sup
t∈[0,T ]
|ψ, (u
k
−u)(t)
H
−s
,H
s
|.
The first term in the right-hand side can be made arbitrarily small, and the
second term is known to tend to 0 since u
k
converges to u in C ([0,T]; H
s
).
Hence the left-hand side also tends to 0.
Secondly, up to translating or/and reversing time, it is sufficient to prove the
right continuity in H
s
of the limit u at t = 0. Furthermore, by a straightforward
ε/3 argument, we have that u(t) − g tends to 0, as t tends to 0+, in H
s
for all
s
<s, and so by the same splitting as before, u(t) tends to g in H
s
w
. In particular,
we have
lim inf
t0
u(t)
H
s
≥g
H
s
.