140 Construction of a symmetrizer under (UKL)
It will be sufficient to prove that each of these spaces F
j
has a limit as (τ,η)
tends to (iρ
0
,η
0
). We select an index j and denote F (τ,η)=F
j
(τ,η), ˆω =ˆω
j
for the sake of simplicity. Let
ˆ
F be a cluster point of F (τ,η)as(τ, η) tends to
(iρ
0
,η
0
). It will be enough to prove the uniqueness of
ˆ
F . By continuity,
ˆ
F is
invariant under A(iρ
0
,η
0
), and is associated to the sole eigenvalue ˆω. Therefore,
we have
ˆ
F ⊂
ˆ
G,where
ˆ
G denotes the generalized eigenspace of A(iρ
0
,η
0
),
associated to the eigenvalue ˆω.
Let us begin with the easy case, when Re ˆω<0. Classically,
ˆ
G locally extends
analytically as an invariant subspace G(τ,η)ofA(τ,η). But since the correspond-
ing eigenvalues will keep a negative real part, we find that G(τ,η) ⊂ E
−
(τ,η), so
that F (τ,η) must be equal to G(τ, η)for(τ, η) close to (iρ
0
,η
0
), and therefore
ˆ
F =
ˆ
G. Notice that this argument can be used to prove that every eigenvalue ω
of A(iρ
0
,η
0
) with negative real part must belong to the list ˆω
1
,...,ˆω
r
,withits
full multiplicity.
There remains the case ˆω = iµ
0
, with µ
0
∈ R. By Proposition 1.7,
we decompose the characteristic polynomial P
τ,η
of A(τ,η)asP
τ,η
(X)=
P
0
(τ,iη,X)Q(τ,iη,X)
q
,whereP
0
and Q are homogeneous polynomials with real
entries and
r
ρ
0
is a simple root of Q(·,η
0
,µ
0
),
r
P
0
(ρ
0
,η
0
,µ
0
) =0.
Let N ≥ 1 be the multiplicity of µ
0
as a root of Q(ρ
0
,η
0
, ·). The eigenvalues of
A(τ,η) that are close to iµ
0
are roots of Q(−iτ, η, −i·) and their multiplicities are
multiples of q.SinceF (τ, η) is the sum of some of the corresponding generalized
eigenspaces, q divides its dimension. We shall denote l := (dim F (τ,η))/q.Then
dim
ˆ
F = lq.
Let O denote the open set of pairs (τ,η) ∈ C × R
d−1
for which the factors
P
k
(τ,iη,·) in (1.5.56) have simple roots, distinct for distinct indices k. Likewise,
we denote by O
C
when allowing complex values for both τ and η. For instance,
(i, 0) ∈Oholds. The complement of O
C
, being the zero set of the discriminant ∆
of Π
L
1
P
k
(τ,η,·), is an algebraic variety of complex codimension one. Therefore,
O
C
is dense and arcwise connected. Likewise, O is dense in C × R
d−1
,for
otherwise the polynomial ∆, vanishing on a non-void open set, would vanish
identically, contradicting the fact that (i, 0) ∈O. We shall admit for a moment
the following
Lemma 5.1 For every pair (τ,η) in O
C
, the matrix A(τ,η) is diagonalizable.
In particular, there is a neighbourhood V of (iρ
0
,η
0
), such that if Re τ>0
and (τ,η) ∈V∩O,thenF (τ, η)isthesumofl eigenspaces, all of them being
of dimension q. Therefore, the minimal polynomial of A over F has the form
Π
l
1
(X − ω
j
(τ,η)). Since O is dense, we obtain by continuity that a polynomial
of degree l annihilates the restriction of A on F , for every (τ,η) ∈V with