Сарычева Л.И. Физика фундаментальных взаимодействий
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l t m
[l] = [t] = [m] =
[l] =
[t] = [m] =
”
“
c
¯h G
N
k N
A
c
¯h c = ¯h = 1
−1
E = mc
2
= m =
l =
¯h
mc
= m
−1
=
−1
t =
¯h
mc
2
=
−1
• m = m · 2 · 10
−27
• l = l (
−1
) · 2 ·10
−11
• t = t
−1
· 6.6 · 10
−22
c
¯h
¯h/mc 3.862 · 10
−11
2.103 · 10
−14
¯h/mc
2
1.288 · 10
−21
7.015 · 10
−25
m 9.109 · 10
−28
1.6726 · 10
−24
mc
2
8.187 · 10
−7
1.503 · 10
−3
c = ¯h =
1
c
G
N
¯h
L =
q
G
N
¯h/c
3
= 1.6 · 10
−33
M =
q
¯hc
G
N
= 2.2 · 10
−5
= 1.2 · 10
19
T =
¯h
M c
2
= 5.4 · 10
−44
G
N
=
L
2
M ·T
2
= 6.67 ·10
−8
2 −1 −2
.
G · M
2
r
= Mc
2
, r = λ =
¯h
Mc
, t =
r
c
.
E =
M
c
2
≃ 10
19
E ≃ 10
19
λ
0
M λ
0
= ¯h/Mc
r
0
=
e
2
m
e
c
2
= 2.81794·1 0
−13
e
m
e
e
ε = γe
2
/r
0
m
e
c
2
a
0
= ¯h
2
/m
e
e
2
a
0
= α/4πR = 0 .529 · 10
−10
α = 1/137
r = 10
−13
10
−8
10
−12
÷ 10
−13
R v
τ =
R
v
=
5·10
−12
10
9
∼ 5 · 10
−22
τ =
10
−13
3·10
10
= 3 ·10
−24
m
m
e
= 10
−27
m
p
= 10
−24
=
1
12
M(
12
)
=
1
16
M(
16
) =
1.66 ·10
−24
M
Q
e = 4.8 ·
10
−10
esu = 1.6 · 10
−19
Q/e = ±1, 0
Q/e = ±2/3 ±1/3
Z
I
J
P
C
G G
I
G
(J
P C
)
h ¯h =
h
2π
= 1.0544 ·10
−27
·
¯h (0, 1, 2, . . .)¯h
(1/2, 3/2, . . .)¯h
J
m = 1
v = r =
J = mvr = L L
J = [~r~p] = 10
27
¯h = 1 ·
¯h = 1.05 · 10
−27
·
J
±1
±1/2
|
~
L|
|
~
S|
|
~
L| = ¯h
q
l(l + 1) l
. . .
|
~
S| = ¯h
q
s(s + 1) s
~
L +
~
S =
~
J
E = mc
2
E
2
= m
2
c
4
+ p
2
c
2
E = mc
2
+ p
2
/2m
m = 0 E = cp
= 1.6 · 10
−12
β =
v
c
c = 3·10
10
γ =
1
√
1−β
2
=
E
mc
2
1 < γ < 2
γ > 2
β
y
y = =
1
2
ln
1+β
1−β
=
1
2
ln
E+p
E−p
∞
β
y
β → 1
E → p
η
η →
1
2
ln tan
θ
2
µ =
1
c
Jπr
2
µ
B
=
e¯h
2m
e
c
= 0.5788 · 10
−14
~µ = g ·µ
B
·
~
J
g
g =
~µ
µ
B
·
~
J
= 2
J =
1
2
¯h
~µ = µ
B
µ =
e¯h/2m
p
c
m
p
”
“
→ → →
”
“
p n π K
J/ψ . . .
∼ 350
”
“
”
“
J = 1/2
B = 1/3 B =
1