
176
Chapter
11. Complexification
and
Classification of Lie
Algebras
(c)
Only
the
root
p
=
0 is degenerate,
and
the
degree of degeneracy l of
this
root
is
characteristic of
.c
and
is
called
the
rank
of
.c.
(d)
The
corresponding
l
"eigenvectors" are elements
Ha
E
.c,
a
=
1,2,
...
,
l;
they
are linearly independent
and
obey
[Ha,Hb]
=0,
a,b=I,2,
...
,l
(11.20)
(e)
The
Ha
for
a
=
1,2,
...
, l
and
En
for
a
E !)to
are independent
and
give
a basis for
.c.
It
must
be clear
that
a "maximal"
A
for which all
this
happens
is
by no
means unique!
At
this
point, we see
that
!)to
consists of
r -
l distinct nonzero
(complex) numbers. We will soon refine
and
get a
better
description of
!)to.
4.
Some
immediate
consequences, on exploiting
the
Jacobi
identities, fol-
low. Since
A
is
a solution
to
(11.18) for
p
=
0,
it
is a linear combination of
the
Ha:
A=.\aH
a
,
.\
a E
C,
not
all identically zero
(11.21 )
Then,
using
the
three-term
Jacobi identity for A,
Ha
and
En,
we get
i.e.
[Ha, En]
=
aaEn,
aa
E
C (11.22)
Thus, for each (complex)
number
a E !)to,
there
is
a (complex) l-component
"root
vector"
{aa},
and
since from Eqs.(11.19),(11.21),(11.22), we get
(11.23)
each vector
{aa}
cannot
vanish identically.
In
fact we
can
say:
a
E!)to
=?
{aa}
i=
0;
a,
(3
E !)to,
a
i=
(3
=?
{aa}
i=
{(3a}.
(11.24)
The
set
!)to
consists of
r - l
distinct non-zero (complex)
numbers.
Let us
now define
!)t
to
be
the
set
of the
corresponding
r -
l
distinct
non-vanishing
(complex)
root vectors
Q,
(3,
...
with
components
aa,
(3a'....
Elements of
!)to
and
of
!)t
are
connected
by
Eq.(11.23). We
are
of course free
to
replace
the
Ha
by nonsingular linear combinations of themselves, leaving
the
En
and
the
original A unchanged.
If
we do
this
we will
regard
the
vectors
Q,
(3,
...
E !)t
as
not
having changed,
but
as being resolved in a new basis. -
5.
The
information so far collected
on
the
structure
constants
cjk
is this:
each index
j,
k,
m,
...
=
1,2,
...
,
r
goes
partly
over
a,
b,
...
=
1,2,
...
, l,
and
partly
over
the
r
-l
distinct non-zero numbers a E !)to (or if we wish,
Q
E !)t).
This
is
the
result of using
Ha
and
En
as a basis for
.c.
Then,
(a)
Property
(3d) above
=?
c:J,
=
0
(11.25)