
138
Chapter
8. Review of
Group
Representations
these two representations.
Quite
generally, let representations
DI
(-)
and
D20
on
(both
real
or
both
complex!) linear vector spaces
VI
and
V
2
be given.
First
form
the
direct
sum
vector space
V
=
VI
EEl
V
2
,
so
that
x
E
V
=?
x
=
Xl
+
X2
uniquely,
Xl
E
VI,
X2
E
V2
(8.9)
Then
the
direct
sum
of
the
two representations
DI (.)
and
D2
(.)
is
the
represen-
tation
D(·)
on
V
with
the
action
(8.10)
The
direct
sum
construction
can
obviously be
extended
to
three
or
more sum-
mands.
Go back now
to
a given reducible decomposable
representation
D(·)
on
V.
Now we raise
the
same question of reducibility for
DIO
and
D20.
If
each of
these
is
either irreducible or reducible decomposable, we
can
keep posing
the
same
question for
their
"parts",
and
so on.
If
we
can
in this way
break
up
D(·)
into finally irreducible pieces, we
then
say
that
D(·)
is
a
fully
reducible
representation.
That
is
to
say, a reducible representation
D(·)
on
V
is
fully
reducible if we
are
able
to
express V as
the
direct
sum
of invariant subspaces,
(8.11)
and
D(·)
restricted
to
each of these
is
irreducible. For all
the
groups we shall deal
with, every representation is either irreducible or fully reducible.
In
particular
this
is
true
for all finite groups,
and
also for
any
simple group.
8.3
Equivalence
of
Representations,
Schur's
Lemma
For a given group G, suppose D(·)
and
D'
(.)
are
two representations
on
the
spaces
V
and
V',
both
being real or
both
complex. We say
that
these represen-
tations
are
equivalent if
and
only if
there
is a one-to-one, onto, hence invertible
linear
mapping
T : V
-7
V'
such
that
D'(g)
=
TD(g)T-
I
for all
9
E
G
(8.12)
Clearly,
V
and
V'
must
then
have
the
same
dimension.
In
practice, when we
deal
with
equivalent representations,
the
spaces
V
and
V'
are
the
same.
The
change of basis described in Eq.(8.5) of Section 8.1 leads us from one
matrix
representation
to
another
equivalent one.
In
the
definition of equivalence
of representations given above, no
statem
e
nt
about
the
reducibility or otherwise
of
D(·)
and
D'
(.)
was made. Actually one
can
easily convince oneself
that
two equivalent representations
must
be
both
irreducible, or
both
reducible;
and
in
the
latter
case
both
must
be
decomposable
or
both
indecomposable. For