Лекции по гидрогазодинамике
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µ =
G
G
.
µ
µ = 0.95 −0.99
µ
G =
12
− 14
G = ρ · v · S = ; i +
v
2
2
= i
0
.
S
S
=
ρ · v
ρ ·v
=
k + 1
2
!
1/(k−1)
λ
1 −
k − 1
k + 1
λ
2
!
1/(k−1)
.
G
√
T
0
S p
0
=
v
u
u
u
t
k
R
2
k + 1
!
(k+1)/(k−1)
= .
k = 1.4, R = 287
g = 9.8 /
2
G
√
T
0
g S p
0
' 0.4.
n
(n + 1)
h
01
=
p
01
p
k k+1
p
k
p
k+1
ψ ≈
p
k
ρ
k
+
v
2
k
2
=
p
k+1
ρ
k
.
ρ
k
p = ρ R T
p = 0.5 (p
k
+ p
k+1
)
ρ
k
=
(p
k
+ p
k+1
)
2 R T
0
.
v
k
=
v
u
u
u
t
2 (p
k
− p
k+1
) R T
0
(p
k
+ p
k+1
.
G
k
= ρ
k
v
k
S
G
k
=
(p
k
+ p
k+1
)
2 R T
0
v
u
u
u
t
2 (p
k
− p
k+1
) R T
0
(p
k
+ p
k+1
S =
=
v
u
u
t
(p
2
k
− p
2
k+1
)
2 R T
0
S.
(p
2
k
− p
2
k+1
)
(p
2
k
− p
2
k+1
) =
G
2
k
2 R T
0
S
2
.
G
k
= , k = 1, .....m
1
n
(p
2
01
− p
2
1
) + (p
2
1
− p
2
2
) + ..... + (p
2
m
− p
2
) =
= (p
2
01
− p
2
) =
n
X
k=1
G
2
k
2 R T
0
S
2
=
=
G
2
2 R T
0
S
2
n.
G =
v
u
u
t
(p
2
01
− p
2
)
2 R T
0
n
S.
S
n
1/
√
n
v = v(r)
T
0
=
r ↑, T ↓
T
0
= T +
v(r)
2
2 C
p
= .
v(r) = ω r ω =
T = T
0
−
v(r)
2
2 C
p
= T
0
−
ω
2
r
2
2 C
p
.
T = T =
T
0
= T +
v(r)
2
2 C
p
= T +
ω
2
r
2
2 C
p
.
v
2
max
/(2 C
p
)
v
2
max
/2000
≈ 300 − 400 /c ∆T 50 − 80
C
µ µ = 1 − µ
T
x
T
µ = G /G
∆T = T −T
∆T = T − T
p = 11 T = 20
C
µ = 0.2
T = −48
C
D = 16
d = 7 b × h = 3 × 6
(2 − 3)
C
η
q
=
µ ∆T
∆T
S
,
∆T
S
η
q
24 − 25%
η
q
= 78%
