712 24.
GROUP
REPRESENTATION THEORY
ofwaysby whichwe canreach this goalwill be
xg2),
whichis alsothe dimension
of the irreducible representation
(A)
by Equation (24.9).
Tosee the argumentmore clearly,supposethatwe areinterestedin the dimen-
sion of the irreduciblerepresentationof S4correspondingto (3, I). Then we must
raise the power of
Xl
by 3 and the powerof X2 by I; X3 and X4 will remain intact,
and therefore will not enter in the following discussion.
It
follows that
D(x
j)
is
to be multipliedby
xi
X2, one x-factor at a time, the number of Xl-factorsalways
exceedingthe number of x2-factors.The possible ways of doing this are
xix2'
XrX2XI, XIX2Xr.
(24.61)
Note that as we count the factors from left to right, the number of
XI'S
is always
greater than or equal to the number of
X2
'so
Thus
x2xi
is absent because X2 oc-
curs without
Xl
occurring first.
It
follows that the dimension of the irreducible
representation (3, I) is 3.
A graphical way to arrive at the same result is to draw AI = 3 boxes on top
and
A2
= I box belowit:
DOD
o
The next stepis to fillin the boxes withnumbers correspondingto the position of
Xl (fillingup the firstrow) and
X2 factors (fillingup the second row) in Equation
(24.61). Since in the first term of (24.61), the
XI'S
occupy the first, second, and
third positions, we enter I, 2, and 3 in the first row, and 4 in the second row
correspondingto thelast position occupiedby
X2. Similarly,in the secondterm of
(24.61), the
XI'S
occupythe first, second, and fourth positions;therefore,weenter
I,
2, and 4 in the firstrow,and 3 in the second row correspondingto the position
occupiedby
X2. Finally,in the last termof (24.61), the
XI'S
occupy the first,third,
and fourth positions; therefore, we enter I, 3, and 4 in the first row, and
2 in the
second row correspondingto the position occupied by
X2. The result is the graph
shownbelow:
Young
frame
defined
24.8.3. Definition. Let
(A)
= (AI,
A2,
...
, An) be a partition
of
n. The Young
frame (or the Young pattern) associated with
(A) is a collection
of
rows
of
boxes
(squares) aligned at the left such that the first row has AI boxes, the second row
A2
boxes, etc. Since Ai 2: AH
J,
the length
of
the rows decreases as one goes to the
bottom
of
theframe.
The Youngframe associated with
(A)
represents
xt'
...
x;",
which multiplies
the antisymmetric polynomial
D(xj).
To find the dimension of the irreducible
representation
T(A),
we have to count the number of ways in which the x-factors
can be permuted among themselves such that as we scan the product, thenumber
of
Xi'S
is neverlessthan number of X
/s
if
j > i. This leads to