m
1
v
2
1
2
+
m
2
v
2
2
2
=
m
1
u
2
1
2
+
m
2
u
2
2
2
(2)
u
2
u
2
=
m
1
m
2
(v
1
+ u
1
) − v
2
m
1
v
2
1
+ m
2
v
2
2
= m
1
u
2
1
+ m
2
h
m
1
m
2
(v
1
+ u
1
) − v
2
i
2
4 · 5
2
+ 6 · 2
2
= 4 · u
2
1
+ 6 ·
h
4
6
(5 + u
1
) − 2
i
2
124 = 4 · u
2
1
+ 6 ·
h
4
3
+
2
3
· u
1
i
2
u
1
u
2
1
+ 1, 6u
1
− 17 = 0
u
1
= −0, 8 ±
q
(0, 8)
2
+ 17 = −0, 8 ± 4, 2;
u
1
= −0, 8 − 4, 2 = −5 /
u
1
= −0, 8 + 4, 2 = 3, 4 / ; u
2
=
4
6
(5 + 3, 4) − 2 = 3, 6
/
m = 35 ; v = 0, 2 / ;
∆l = 12 .
F
max
, ∆t
L
L
L
B
B
B
m
m m
v
=
k∆l
2
2
=
mv
2
2
k
k =
mv
2
∆l
2
=
35 · 10
3
· (0, 2)
2
(0, 12)
2
= 9, 72 · 10
4
.
F
max
= k · ∆l = 9, 72 · 10
4
· 0, 12 = 1, 17 · 10
3
.