282 Random Dynamical Systems
following two conditions, which only require α
n
to be continuous and
not necessarily Lipschitz. We have proved
Proposition 7.1 On a complete separable metric space, let α
n
(n ≥ 1)
be i.i.d. continuous. The Markov process X
n
(x) ≡ α
n
···α
1
x is stable in
distribution if
(a) sup{d(α
n
α
n−1
···α
1
x,α
n
α
n−1
···α
1
y): d(x, y) ≤ M}→0 in
probability, as n →∞, for every M > 0,
and
(b) for some x
0
∈ S, the sequence of distributions of d(X
n
(x
0
), x
0
) ≡
d(α
n
···α
1
x
0
, x
0
) is relatively weakly compact.
When S is compact, then (b) is automatic, since the sequence
d(X
n
(x
0
), x
0
) is bounded by the diameter of S, whatever be x
0
and n.
Obviously here one may simplify the statement of (a) by taking just one
M, namely, the diameter of S:
(a)
: diam(α
n
α
n−1
···α
1
S) → 0 in probability as n →∞.
The criterion (a)
is now used to prove the following basic result of
Dubins and Freedman (1966).
Theorem 7.3 Let (S, d) be compact metric and the set of all contrac-
tions on S. Let Q be a probability measure on the Borel sigmafield of
(with respect to the “supremum” distance) such that the support of
Q contains a strict contraction. Then the Markov process X
n
defined
by (2.1) and (2.2) has a unique invariant probability and is stable in
distribution.
Proof. Let γ be a strict contraction in the support of Q, i.e.,
d(γ x,γy) < d(x, y)∀x = y.
As before, the jth iterate of γ is denoted by γ
j
. Since γ
j+1
S =
γ
j
(γ S) ⊂ γ
j
S, it follows that γ
j
S decreases as j increases. Indeed
γ
j
S decreases to ∩
∞
j=1
γ
j
S = a singleton {x
0
}. (7.22)
To see this, first note that the limit is nonempty, by the finite inter-
section property of (S, d), and the fact that γ
j
S is the continuous
image of a compact set S and therefore, closed (compact). Assume,
if possible, that there are points x
0
, y
0
in the limit set, x
0
= y
0
. Let