4.5 A snag, and the need for a significant complication 65
the gauge group. When interactions are included, we arrive at supersymmetrized
versions of the SM gauge theories (see Chapter 7).
This is an appropriate point to explain why only N = 1 SUSY (see the preceding
footnote) has been considered. The reason is that in N = 2 SUSY the corresponding
chiral multiplet contains four states: λ =+
1
2
,λ =−
1
2
and two states with λ = 0.
The phenomenological problem with this is that the R (λ =
1
2
) and L (λ =−
1
2
)
states must transform in the same way under any gauge symmetry (similar remarks
hold for all N ≥ 1 supermultiplets). But we know that the SU(2)
L
gauge symmetry
of the SM treats the L and R components of quark and lepton fields differently. So
if we want to make a SUSY extension of the SM, it can only be the simple N = 1
SUSY, where we are free to treat the left chiral supermultiplet (λ =−
1
2
,λ = 0)
differently from the right chiral supermultiplet (λ = 0,λ =+
1
2
). Further details of
the representations for N ≥ 1 are given in [42] Section 1.6, for example.
One other case of possible physical interest is the gravity supermultiplet, contain-
ing a spin-2 graviton state with λ =−2 and a spin-
3
2
gravitino state with λ =−
3
2
.
The interacting theory here is supergravity, which however lies beyond our scope.
We must now take up an issue raised after (4.36).
4.5 A snag, and the need for a significant complication
In Section 4.2 we arrived at the SUSY algebra by calculating the difference δ
η
δ
ξ
−
δ
ξ
δ
η
two different ways. We explicitly evaluated this difference as applied to φ,
but in deducing the operator relation (4.37), it is crucial that a consistent result be
obtained when δ
η
δ
ξ
− δ
ξ
δ
η
is applied to χ. In fact, as noted after (4.38), this is not
the case, as we now show. This will necessitate a significant modification of the
SUSY transformations given so far, in order to bring about this desired consistency.
Consider first δ
η
δ
ξ
χ
a
, where we are indicating the spinor component explicitly:
δ
η
δ
ξ
χ
a
= δ
η
(−iσ
μ
(iσ
2
ξ
∗
))
a
∂
μ
φ
= (iσ
μ
(−iσ
2
ξ
∗
))
a
∂
μ
δ
η
φ
= (iσ
μ
(−iσ
2
ξ
∗
))
a
(η
T
(−iσ
2
)∂
μ
χ). (4.98)
There is an important identity involving products of three spinors, which we can
use to simplify (4.98). The identity reads, for any three spinors λ, ζ and ρ,
λ
a
(ζ
T
(−iσ
2
)ρ) + ζ
a
(ρ
T
(−iσ
2
)λ) + ρ
a
(λ
T
(−iσ
2
)ζ ) = 0, (4.99)
or in the faster notation
λ
a
(ζ · ρ) + ζ
a
(ρ · λ) + ρ
a
(λ · ζ ) = 0. (4.100)
Exercise 4.2 Check the identity (4.99).