C.6 The Tensor and Exterior Algebra 881
Proof. This is an easy exercise working through the definitions. Note that the left side
of equation (C.12b) has a tensor product of simply “elements” or symbols a
i
that happen
to belong to V* whereas the right side is a tensor product of maps as defined by (C.7).
Because multilinear maps are more intuitive than abstract tensor products,
Theorem C.6.6 justifies our always treating T(V*) as if it were L(V). Notice, however,
that we had to use the dual space V* to make this identification.
Now we move on to a definition of exterior algebras. Let S
k
be the group of per-
mutations of {1,2, . . . ,k}. Any element s of S
k
induces a unique isomorphism
(C.13a)
satisfying
(C.13b)
Definition. A tensor a in T
k
V is said to be alternating if s(a) = sign(s)a, for all sŒ
S
k
. A linear transformation
is said to be alternating if T s=sign(s)T, for all sŒS
k
.
Now, by Theorem C.6.6 we can identify T
k
(V*) with (T
k
V)*.
C.6.7. Theorem. A tensor in T
k
(V*) is alternating if and only if it corresponds to an
alternating linear transformation in (T
k
V)* under the natural isomorphism j defined
by Theorem C.6.5(2).
Proof. See [AusM63].
Definition. The alternation map Alt:T
k
V Æ T
k
V is defined by
C.6.8. Theorem.
(1) The alternation map Alt:T
k
V Æ T
k
V is a linear transformation.
(2) If aŒT
k
V, then Alt(a) is an alternating tensor.
(3) If aŒT
k
V is an alternating tensor, then Alt(a) =a.
Proof. This is an easy exercise.
Theorem C.6.8 shows that Alt
2
= Alt, so that Alt is a projection of T
k
V onto the
subspace of alternating tensors.
,.
,.